How do I break this while loop? [python]

Question

I'm tying to make it so when you enter a digit value in the while loop, the loop ends and so does the program. However when I type "break" I get an invalid syntax error:(. Sorry for the bad coding, this is my first time.

print('Hello, world!')
print('What is your name?')
myName = input()
print('It is nice to met you, '+ myName)
print('The length of your name is:')
print(len(myName))
print('What is your age?')
myAge=input()
if myAge.isdigit():print('You will be ' + str(int(myAge) + 1) + ' in "one" year')
else: print('that is not a number. Lets try again, what is your age?')
C = 0
while (C<=3):
    myAge2=input()
    C+=1
    if myAge2.isdigit():print('You will be ' + str(int(myAge2) + 1) + ' in "one" year')
    break
    else: print('Try again')

Indent breakafter the if - also drop the codeblock after the if and else to a newline — leopardxpreload
– leopardxpreload, Commented Jun 22, 2020 at 5:47

leopardxpreload · Accepted Answer · 2020-06-22 05:48:19Z

2

Indentation to apply the correct break

 if myAge2.isdigit():
    print('You will be ' + str(int(myAge2) + 1) + ' in "one" year')
    break
 else: 
    print('Try again')

answered Jun 22, 2020 at 5:48

leopardxpreload

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Comments

Dwight · Accepted Answer · 2020-06-22 06:05:19Z

0

I tried simplifying the code:

print('Hello, world!\nWhat is your name')
myName = input()
print('It is nice to met you, {}.\nThe length of your name is: {}'.format(myName, len(myName)))
print('What is your age?')
myAge=input()
if myAge.isdigit():
  print('You will be ' + str(int(myAge) + 1) + ' in "one" year')
else: 
  print('that is not a number. Lets try again, what is your age?')

myAge2=input()
while myAge2.isdigit():
  print('You will be ' + str(int(myAge2) + 1) + ' in "one" year')
  break
else:  
  print('Try again')

edited Jun 22, 2020 at 6:05

answered Jun 22, 2020 at 5:59

Dwight

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Comments

Alok Tripathi · Accepted Answer · 2020-06-22 06:12:13Z

0

Problem with the code indentation, otherwise everything is working perfectly.

print('Hello, world!')
print('What is your name?')
myName = input()
print('It is nice to met you, ' + myName)
print('The length of your name is:')
print(len(myName))
print('What is your age?')
myAge = input()
if myAge.isdigit():
    print('You will be ' + str(int(myAge) + 1) + ' in "one" year')
else:
    print('that is not a number. Lets try again, what is your age?')
C = 0
while (C <= 3):
    myAge2 = input()
    C += 1
    if myAge2.isdigit():
        print('You will be ' + str(int(myAge2) + 1) + ' in "one" year')
        break
    else:
        print('Try again')

Output

answered Jun 22, 2020 at 6:12

Alok Tripathi

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