Find value using python regex in a string

Question

In this example I need salt value in both strings.

string = 'SHA-224(Salt len: 20)'

string2 = '# Salt len: 0' 
 
pattern = re.compile(r'^(#\s)?((SHA-\d+)?\(?Salt len: \d+\)?)') 
 
result = pattern.search(string)  

result2 = pattern.search(string2)

print(result)

print(result2)

Expected output:
20
0

please help me guys

Is this working for you?

Toto
– Toto

2020-06-22 09:33:04 +00:00
Commented Jun 22, 2020 at 9:33 — Toto
– Toto, Commented Jun 22, 2020 at 9:33

Wiktor Stribiżew · Accepted Answer · 2020-06-22 09:33:03Z

1

You may use a simpler pattern that will match Salt len:, spaces and then captures any amount of digits:

pattern = re.compile(r'\bSalt len: (\d+)')

See the regex demo.

Details

\b - a word boundary
Salt len: - a string
(\d+) - Capturing group 1: one or more digits

When using in Python, check for a match first:

result = pattern.search(string)

Then, check if there was a match, and if yes, extract Group 1 value.

Python demo:

import re
texts = ['SHA-224(Salt len: 20)', '# Salt len: 0']
pattern = re.compile(r'\bSalt len: (\d+)') 
for text in texts:
    result = pattern.search(text)
    if result:
        print(result.group(1))

answered Jun 22, 2020 at 9:33

Wiktor Stribiżew

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