Nested Dictionary Python:Update logic failing

Question

My dictionary :

d={'a':'a1,a2,a3,a4','b':'b1,b2,b3,b4',c:'c1,c2,c3,c4'}

and so on d,e,f,....

d2={'a1':'a11,a12,a13,a14,a15','a2':'a21,a22,a23,a24,a25'}

and so on for a3,a4,a5,b1,b2....

Expected output

dict1={'a':{'a1':'a11,a12,a13,a14,a15','a2':'a21,a22,a23,a24,a25'}}

and so on for rest

My Output

dict1={'a':{'a1':'a11,a12,a13,a14,a15'},'a2':'a21,a22,a23,a24,a25'}

and so on then again

 'b':{'b1':'b11,b12,b13,b14,b15'},'b2':'b21,b22,b23,b24,b25'}

My Code:

dict1={}
for i in d:
    q=d[i].split(",")
    for j in q:
        dict1[i] = {}
        if j in d2:
            dict1[i][j] = d2[j]
            dict1.update(dict1[i])

Any help would be very useful

Leo Arad · Accepted Answer · 2020-06-23 07:19:13Z

1

You can try nested dictionary comprehension with list comprehension

d={'a':'a1,a2,a3,a4','b':'b1,b2,b3,b4','c':'c1,c2,c3,c4'}
d2={'a1':'a11,a12,a13,a14,a15','a2':'a21,a22,a23,a24,a25', 'b1':'b11,b12,b13,b14,b15','b2':'b21,b22,b23,b24,b25'}
dict1 = {k: {i: d2[i] for i in v.split(",") if i in d2} for k, v in d.items()})
print(dict1)

Output in this case

{'a': {'a1': 'a11,a12,a13,a14,a15', 'a2': 'a21,a22,a23,a24,a25'}, 'b': {'b1': 'b11,b12,b13,b14,b15', 'b2': 'b21,b22,b23,b24,b25'}, 'c': {}}

So if there will be values in d2 about the the c's they will be in the dict1 results as well.

answered Jun 23, 2020 at 7:19

Leo Arad

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Comments

Anton Erholt · Accepted Answer · 2020-06-23 07:13:16Z

0

Maybe you can try with:

dict1={}
for i in d:
    q=d[i].split(",")
    for j in q:
        if not dict1.get(i, None):
            dict1[i] = {}
        if j in d2:
            dict1[i][j] = d2[j]

answered Jun 23, 2020 at 7:13

Anton Erholt

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