Removing value from array in JS

Question

Im new to software development and have been taking a class, im having an issue with finding out how to remove items in an array based on a 2nd argument character

Write a function "removeWordsWithChar" that takes 2 arguments:

an array of strings
a string of length 1 (ie: a single character) It should return a new array that has all of the items in the first argument except those that contain a character in the second argument (case-insensitive).

Examples:

----removeWordsWithChar(['aaa', 'bbb', 'ccc'], 'b') --> ['aaa', 'ccc']

----removeWordsWithChar(['pizza', 'beer', 'cheese'], 'E') --> ['pizza']

function removeWordsWithChar(arrString, stringLength) {
  const arr2 = [];
 for (let i = 0; i < arrString.length; i++) {
   const thisWord = arrString[i];
    if (thisWord.indexOf(stringLength) === -1) {
     arr2.push(thisWord);
    }
  }
return arr2;
}

Array.prototype.filter arr2.filter(x=>!x.toLowerCase().includes(strLength.toLowerCase())) — user120242
– user120242, Commented Jun 23, 2020 at 22:06
it should be case insensitive, so use if (thisWord.toLowerCase().indexOf(stringLength.toLowerCase()) === -1) — CascadiaJS
– CascadiaJS, Commented Jun 23, 2020 at 22:09
that worked! i cant believe i missed the lowercase. Thank you! — adeel-justice
– adeel-justice, Commented Jun 23, 2020 at 22:13
you can also use localeCompare developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/… — user120242
– user120242, Commented Jun 23, 2020 at 22:15
Does this answer your question? How to do case insensitive string comparison? — user120242
– user120242, Commented Jun 23, 2020 at 22:15

mgm793 · Accepted Answer · 2020-06-23 22:11:50Z

1

As they said in comments you can use filter like this:

function removeWordsWithChar(elems, string){
  return elems.filter(elem => !elem.toLowerCase().includes(string.toLowerCase()));
}

answered Jun 23, 2020 at 22:11

mgm793

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