Parsing the String to different format in Python

Question

I have a text document and I need to add two @ symbols before the keywords present in an array.

Sample text and Array:

str ="This is a sample text document which consists of all demographic information of employee here is the value you may need,name: George employee_id:14296blood_group:b positive this is the blood group of the employeeage:32"

arr=['name','employee_id','blood_group','age']

Required Text:

str ="This is a sample text document which consists of all demographic information of employee here is the value you may need, @@name: George @@employee_id:14296 @@blood_group:b positive this is the blood group of the employee @@age:32"

Pani · Accepted Answer · 2020-06-25 10:15:11Z

1

Just use the replace function

str ="This is a sample text document which consists of all demographic information of employee here is the value you may need,name: George employee_id:14296blood_group:b positive this is the blood group of the employeeage:32"
arr = ['name','employee_id','blood_group','age']

for w in arr:
    str = str.replace(w, f'@@{w}')
print(str)

answered Jun 25, 2020 at 10:15

Pani

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Comments

Ronald · Accepted Answer · 2020-06-25 10:17:43Z

0

You can simply loop over arr and use the str.replace function:

for repl in arr:
    strng.replace(repl, '@@'+repl)
    
print(strng)

However, I urge you to change the variable name str because it is a reserved keyword.

answered Jun 25, 2020 at 10:17

Ronald

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Comments

Daweo · Accepted Answer · 2020-06-25 10:20:25Z

You might use re module for that task following way

import re
txt = "This is a sample text document which consists of all demographic information of employee here is the value you may need,name: George employee_id:14296blood_group:b positive this is the blood group of the employeeage:32"
arr=['name','employee_id','blood_group','age']
newtxt = re.sub('('+'|'.join(arr)+')',r'@@\1',txt)
print(newtxt)

Output:

This is a sample text document which consists of all demographic information of employee here is the value you may need,@@name: George @@employee_id:14296@@blood_group:b positive this is the blood group of the employee@@age:32

Explanation: here I used regular expression to catch words from your list and replace each with @@word. This is single pass, as opposed to X passes when using multiple str.replace (where X is length of arr), so should be more efficient for cases where arr is long.

Yogesh · Accepted Answer · 2020-06-25 10:25:07Z

0

As an alternative, you can convert the below in a loop for lengthier list. There seems to be space before @@ too.

str= str[:str.find(arr[0])] + ' @@' + str[str.find(arr[0]):]

str= str[:str.find(arr[1])] + ' @@' + str[str.find(arr[1]):]

str= str[:str.find(arr[2])] + ' @@' + str[str.find(arr[2]):]

str= str[:str.find(arr[3])] + ' @@' + str[str.find(arr[3]):]

answered Jun 25, 2020 at 10:25

Yogesh

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Comments

Leo Arad · Accepted Answer · 2020-06-25 10:25:19Z

0

You can replace the value and add space and double @@ before the replaced value and in the result replace double spaces with one space.

str ="This is a sample text document which consists of all demographic information of employee here is the value you may need,name: George employee_id:14296blood_group:b positive this is the blood group of the employeeage:32"
arr=['name','employee_id','blood_group','age']

for i in arr:
    str = str.replace(i, " @@{}".format(i))
print(str.replace("  ", " "))

Output

This is a sample text document which consists of all demographic information of employee here is the value you may need, @@name: George  @@employee_id:14296 @@blood_group:b positive this is the blood group of the employee @@age:32

edited Jun 25, 2020 at 10:25

answered Jun 25, 2020 at 10:20

Leo Arad

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