largest and smallest number using input while loop python

Question

This is my try to write a program that repeatedly prompts a user for integer numbers until the user enters done. Once done is entered, print out the largest and smallest of the numbers. If the user enters anything other than a valid number catch it with a try/except and put out an appropriate message and ignore the number. Enter 7, 2, bob, 10 and 4 and match the output below. But it's false. I need some help can someone explain my fault.

largest = 0
smallest = 0



while True:
    num = input("Enter a number: ")
    if num =="done": break
    try:
           fnum = float(num)
    except:
        print("Invalid input")
        continue

    if largest == 0 or num >= largest: largest = num
    else: largest= largest
    if smallest == 0 or num <= smallest: smallest = num
    else: smallest= smallest

print("Maximum is", largest)
print("Minimum is", smallest)

Just Fyi we have min/max builtin functions in this language

cs95
– cs95

2020-06-28 22:51:10 +00:00
Commented Jun 28, 2020 at 22:51 — cs95
– cs95, Commented Jun 28, 2020 at 22:51
i know but i really need to got this

medgr198
– medgr198

2020-06-28 22:54:57 +00:00
Commented Jun 28, 2020 at 22:54 — medgr198
– medgr198, Commented Jun 28, 2020 at 22:54

Red · Accepted Answer · 2020-06-28 22:56:44Z

1

Instead, why don't you a list to store the values, then you can use the min and max methods:

nums = []

while True:
    num = input("Enter a number: ")
    if num == "done" : break
    try:
        fnum = float(num)

    except:
        print("Invalid input")
        continue

    nums.append(fnum)

largest = max(nums)
smallest = min(nums)

print("Maximum is", largest)
print("Minimum is", smallest)

answered Jun 28, 2020 at 22:56

Red

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Comments

jec1918 · Accepted Answer · 2020-06-28 23:01:24Z

0

You should be using fnum in those if statements, not num.

answered Jun 28, 2020 at 23:01

jec1918

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