JS remove elements from array of objects if element value is in another array

Question

I have array

[
["BS-BLACK-2", ..., "0"]
["BS-BLACK-3", ..., "0"],
["BS-BLACK-4", ..., "0"],
["BS-BLACK-5", ..., "0"]
]

And another array

["BS-BLACK-2","BS-BLACK-3"]

How to exclude all elements in 1st array if values found in second array. to have:

[["BS-BLACK-4", ..., "0"],["BS-BLACK-5", ..., "0"]]

I use below code but it works only with not nested arrays

newArray= oldArray.filter(function (el) {
             return !toExcludeAray.includes(el);
}

Are the values to exclude always at index 0 in the nested arrays? — M0nst3R
– M0nst3R, Commented Jun 30, 2020 at 12:45

M0nst3R · Accepted Answer · 2020-06-30 12:51:04Z

1

You can use includes() inside a filter() call on your input data to exclude the elements based on the second array. [firstValue] corresponds to destructuring the first value in the nested array element.

const input = [
    ["BS-BLACK-2", "0"],
    ["BS-BLACK-3", "0"],
    ["BS-BLACK-4", "0"],
    ["BS-BLACK-5", "0"]
];
const toExclude = ["BS-BLACK-2","BS-BLACK-3"];
const filtered = input.filter(([firstValue]) => (!toExclude.includes(firstValue)));
console.log(filtered);

answered Jun 30, 2020 at 12:51

M0nst3R

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Comments

Sudhir Ojha · Accepted Answer · 2020-06-30 12:49:24Z

0

You can use el[0] if BS-BLACK-2, BS-BLACK-3.. always at 0th index.

let oldArray = [
["BS-BLACK-2", "0"],
["BS-BLACK-3", "0"],
["BS-BLACK-4", "0"],
["BS-BLACK-5", "0"]
];


let toExcludeAray = ["BS-BLACK-2","BS-BLACK-3"];

let newArray = oldArray.filter(function (el) {
   return !toExcludeAray.includes(el[0]);
});
console.log(newArray);

answered Jun 30, 2020 at 12:49

Sudhir Ojha

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