How to Write An Instance Of an Added Element When Using array.splice()?

Question

I'm trying to create an instance of the elements that have been added using the splice() function.

var myFish = ['angels', 'clowns', 'starfish', 'sharks'];
var removed = myFish.splice(2,1, "spongebob"); 
console.log(removed); //

The output I'm looking for is spongebob but instead I get starfish.

Any thoughts?

Are you trying to replace starfish with spongebob because if so, you did that successfully. removed is showing the element that you spliced out of the array. If you actually console.log(myFish), you will see that your array now includes spongebob. — AttemptedMastery
– AttemptedMastery, Commented Jun 30, 2020 at 15:20
Why use splice in the first place if you don't want the removed item? Simply do: var added = myFish[2] = "spongebob"; — ibrahim mahrir
– ibrahim mahrir, Commented Jun 30, 2020 at 15:26

ffritz · Accepted Answer · 2020-06-30 15:30:24Z

2

Array.splice returns the deleted elements, not the mutated array.

var myFish = ['angels', 'clowns', 'starfish', 'sharks'];
console.log("Array before we splice: ", myFish);
var removed = myFish.splice(2,1, "spongebob");
console.log("Array after we splice: ", myFish);
console.log("Replaced Element ", removed, "with: ", myFish[2]);

edited Jun 30, 2020 at 15:30

answered Jun 30, 2020 at 15:22

ffritz

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Comments

sonEtLumiere · Accepted Answer · 2020-06-30 15:32:00Z

0

You are splicing by index 2 (starfish), remove 1 element and replace with 'spongebob'. starfish is removed and stored in removed var.

var myFish = ['angels', 'clowns', 'starfish', 'sharks'];
var removed = myFish.splice(2, 1, "spongebob");
console.log(myFish);  //["angels", "clowns", "spongebob", "sharks"]
console.log(myFish[2]); // spongebob
console.log(removed); // ["starfish"]

edited Jun 30, 2020 at 15:32

answered Jun 30, 2020 at 15:24

sonEtLumiere

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1 Comment

Edward Casanova Over a year ago

thanks man! haha sometimes i appear to overcomplicate things :)

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