Finding all combinations of an array that include all values in JavaScript [duplicate]

Question

Lets say i have an array with 3 numbers:

[1,2,3]

I want to find all combinations of this 3 numbers where all the numbers are included.

Output should look like this:

[1,2,3], [1,3,2], [3,1,2], [3,2,1], [2,3,1], [2,1,3]

i need only combinations including all 3 numbers and also i need any given combination of them. 3,2,1 ≠ 1,2,3. Also i dont need 1,1,2 or 1,2,2 etc. Every number can only occure once. — Herbo
– Herbo, Commented Jul 1, 2020 at 2:07

freqnseverity · Accepted Answer · 2020-07-01 02:12:39Z

0

It's a bit brute force, but if you're only going to have to do this for a list of three elements, this is simple enough.

a = [1, 2, 3]
a_comb = [[a[0],a[1],a[2]], [a[0], a[2], a[1]], [a[2], a[0], a[1]], [a[2], a[1], a[0]], [a[1],a[0],a[2]], [a[1],a[2],a[0]]]

answered Jul 1, 2020 at 2:12

freqnseverity

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