I have this very simple code that gets a dictionary as imput and returns back a dictionary as well:
app = FastAPI()
class User(BaseModel):
user_name: dict
@app.post("/")
def main(user: User):
## some processing
return user
I'm calling this with the following python code:
import requests
import json
import pandas as pd
df = pd.read_csv("myfile.csv")
data = {}
data["user_name"] = df.to_dict()
headers = {'content-type': 'application/json'}
url = 'http://localhost:8000/'
resp = requests.post(url,data=json.dumps(data), headers=headers )
resp
Now, I want to do something similar but instead of sending the data with a request from python I want to upload a local file send it to the API and get a processed .csv file back.
Now I have the following code to upload a file:
from typing import Optional
from fastapi import FastAPI
from fastapi import FastAPI, File, UploadFile
from pydantic import BaseModel
from typing import List
from fastapi.responses import HTMLResponse
app = FastAPI()
class User(BaseModel):
user_name: dict
@app.post("/files/")
async def create_files(files: List[bytes] = File(...)):
return {"file_sizes": [len(file) for file in files]}
@app.post("/uploadfiles/")
async def create_upload_files(files: List[UploadFile] = File(...)):
return {"filenames": [file.filename for file in files]}
@app.get("/")
async def main():
content = """
<body>
<form action="/files/" enctype="multipart/form-data" method="post">
<input name="files" type="file" multiple>
<input type="submit">
</form>
</body>
"""
return HTMLResponse(content=content)
This allows me to select and load a file:
But when I click on send, I'm redirected to: http://localhost:8000/uploadfiles/ and get the following error:
{"detail":"Method Not Allowed"}
How can I send the file for procesing to the API and get a file back as a response?
