Using fuzzy regex with variable while still specifying error

Question

I'm using the regex library in python and trying to do fuzzy matching.

I need to use a variable in my search string and this is the code I got following this post

x = regex.search(rf"(?b){variable}{d}",s)

which gives NameError: name 'd' is not defined

The issue is that I want to specify the type of error with the {d} tag but that is also interpreted as a variable. The only solution I have come up with so far is just to assign d = "d". Looking for a more "proper" way to accomplish this.

Example case:

variable = "amazing"
s = 'amaing analogy'
x = regex.search(rf"{variable}{d}",s)
x.group()

intended output : "amaing"

Leo Arad · Accepted Answer · 2020-07-08 06:14:52Z

1

You can escape the currently brackets by adding another currently brackets

x = regex.search(rf"(?b){variable}{{d}}",s)

answered Jul 8, 2020 at 6:14

Leo Arad

4,4822 gold badges8 silver badges17 bronze badges

Sign up to request clarification or add additional context in comments.

1 Comment

data_steve Over a year ago

@zhao @leo what is this d syntax? I can't find any good documentation or examples on how to use error tag {e<=1} or {e<=.97} type examples.

Collectives™ on Stack Overflow

Using fuzzy regex with variable while still specifying error

1 Answer 1

1 Comment

Your Answer

Linked

Hot Network Questions

Collectives™ on Stack Overflow

1 Answer 1

1 Comment

Your Answer

Sign up or log in

Post as a guest

Linked

Related