PowerShell replace value in an array

Question

I'm quite new in PowerShell and I would need a little bit of support how to replace values in an array. Please have a look at my example:

[array[]]$nodes = @()
[array[]]$nodes = get-NcNode | select-object -property Node, @{Label = "slot"; expression = {@("a")*4}}

$nodes
Node       slot
----       ----
nn01       {a,a,a,a}
nn02       {a,a,a,a}
nn03       {a,a,a,a}
nn04       {a,a,a,a}             
 
$nodes[0].slot[0]
      a

$nodes[0].slot[0] = "b"            #I try to replace a with b
$nodes[0].slot[0]
      a                            #It didn’t work

$nodes[0].slot.SetValue("b",0)     #I try to replace a with b
$nodes[0].slot[0]
      a                            #It didn’t work

$nodes[0] | Add-Member -MemberType NoteProperty -Name slot[0] -Value "b" -Force
$nodes[0]
Node       slot      slot[0]
----       ----      -------
nn01       {a,a,a,a} b              #That’s not what I wanted

$nodes[0].slot[0] = "b" works fine for me. Note that the $nodes array is not inline with your Select-Object expression. If the slot is an array, there should be spaces between the strings in the display output: {a, a, a, a}. I recommend you to use this $Nodes = 1..4 | Select-Object @{n = 'Node'; e = { "nn0$_" }}, @{n = 'Slot'; e = { @('a') * 4 }} for the minimal reproducible example input. — iRon
– iRon, Commented Jul 13, 2020 at 11:44
As an aside: The initialization statement, [array[]]$nodes = @(), is pointless: its effects are replaced by the next [array[]]$nodes = ... statement. — mklement0
– mklement0, Commented Jul 13, 2020 at 12:25
@iRon, the code only works if [array[]] is changed to [array]. — mklement0
– mklement0, Commented Jul 13, 2020 at 12:33

mklement0 · Accepted Answer · 2022-03-10 23:25:46Z

If you really need an array of arrays (type [array[]]), your problem is solved as follows:

$nodes[0][0].slot[0] = "b"

That is, each of your $nodes elements is itself an array, and the way you filled $nodes, each [pscustomobject] instance output by your get-NcNode | select-object ... pipeline became its own element of $nodes, but each as a single-element sub-array - hence the need for the extra [0] index access.^[1]

However, it sounds like a regular array ([array], effectively the same as [object[]]) is sufficient in your case, where each element holds a (single, scalar) [pscustomobject]:

# Type constraint [array] creates a regular [object[]] array.
[array] $nodes = get-NcNode | select-object -property Node, @{Label = "slot"; expression = {@("a")*4}}

With $nodes defined like this, your original code should work.

^{[1] On getting a value - but not on setting - you can get away without the extra index, thanks to PowerShell's member-access enumeration feature.}

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