Regular expression is not working in python script

Question

the regular expression is not working. please find the below details.

cpu_pattern = re.compile('.*CPU.*(usr|user).*nice.*sys.*')

part = b'11:40:24 AM     CPU      %usr     %nice      %sys   %iowait    %steal      %irq     %soft    %guest     %idle\n11:40:25 AM     all      0.00      0.00      0.08      0.00      0.00      0.00      0.00      0.00     99.92'

IF condition:

if cpu_pattern.search(part): if cpu_usage == '': cpu_usage == part

Error:

TypeError('cannot use a string pattern on a bytes-like object')

As the error says, You 'cannot use a string pattern on a bytes-like object'. Your search-pattern is a string, the part variable is bytes. — Hampus Larsson
– Hampus Larsson, Commented Jul 17, 2020 at 8:29

Ashish Karn · Accepted Answer · 2020-07-17 09:10:01Z

1

Please use below code to convert byte to string in python which will solve your issue:

part= part.decode("utf-8")

Put above code after part obejct

Output print(part):

11:40:24 AM     CPU      %usr     %nice      %sys   %iowait    %steal      %irq     %soft    %guest     %idle                         
11:40:25 AM     all      0.00      0.00      0.08      0.00      0.00      0.00      0.00      0.00     99.92

answered Jul 17, 2020 at 9:10

Ashish Karn

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Comments

Konrad Rudolph · Accepted Answer · 2020-07-17 10:26:33Z

0

part is not a string, it’s a byte sequence. You now have two choices; which is more appropriate depends on how part was generated:

Perform byte-wise matching rather than string matching, by using a byte sequence pattern:
```
cpu_pattern = re.compile(b'.*CPU.*(usr|user).*nice.*sys.*')
```
Decode the parts byte sequence using an appropriate encoding, e.g. UTF-8:
```
parts_str = parts.decode('utf-8')
```

answered Jul 17, 2020 at 10:26

Konrad Rudolph

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1 Comment

nallapayan 420 Over a year ago

**cpu_usage += "\n" + part ** Can only concatenate str (not "bytes") to str

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