Integer returning NumberFormatException when parsing using Integer.parseInt

Question

I am working on a project that requires me to parse a String into an Integer. I have not had this problem before, but when I try to parse a String to an Integer, I get this message

Exception in thread "main" java.lang.NumberFormatException: For input string: "385.3100", where 385.3100 is the integer in question. Nothing I have done is working.

String close = (closing.get("4. close").toString()); int money = Integer.parseInt(close); Is my code, where closing is a JSONObject.

Any help would be appreciated!

Yeah, that worked. I don't know how I forgot to do that, but I appreciate the timely response! Thank you! — Mischef9
– Mischef9, Commented Jul 18, 2020 at 17:41

Ayush28 · Accepted Answer · 2020-07-18 17:42:36Z

1

385.3100 is not an integer but a number with decimal precision. Use:

Double.parseDouble() or Float.parseFloat()

answered Jul 18, 2020 at 17:42

Ayush28

3793 silver badges18 bronze badges

Sign up to request clarification or add additional context in comments.

Collectives™ on Stack Overflow

Integer returning NumberFormatException when parsing using Integer.parseInt

1 Answer 1

Comments

Your Answer

Hot Network Questions

Collectives™ on Stack Overflow

1 Answer 1

Comments

Your Answer

Sign up or log in

Post as a guest

Related