Python numpy - fill numpy array with ascending values

Question

I am trying to initialize a numpy array or a list with ascending values. The number of values is n.

e.g: If n = 10

[0,2,4,6,8,10,12,14,16,18]

If n = 2

[0,2]

I am aware that I could use a for like this:

result = []
for x in range(n):
   result.append(x*2)

But when n gets larger this would take a while so I was looking for a faster way.

a_guest · Accepted Answer · 2020-07-29 14:46:06Z

7

There is numpy.arange which supports a step parameter:

result = np.arange(0, 2*n, 2)

answered Jul 29, 2020 at 14:46

a_guest

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Comments

C.Nivs · Accepted Answer · 2020-07-29 14:47:20Z

1

Alternatively, for a list you can use range's step parameter:

result = list(range(0, 2*n, 2))

answered Jul 29, 2020 at 14:47

C.Nivs

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