How to fetch only the values from an object ignoring the null values in NodeJS?

Question

I have an object saResponse which looks as below:

0: {severity: "Low", assignee: null, notesType: "Type1", notes: "Notes1", createdAt: "2020-07-29"}
length: 1

I want to convert this Object into String such that only values are displayed separted by :: and ignoring null values.

Desired Output

Low::Type1::Details1::2020-07-29

I have added below code but it is not giving desired output

 const saValue = Object.values(saResponse).map
                (el => Object.entries(el).filter(([key, value]) => value !== null).reduce((acc, [key, value]) => ({
                    ...acc,
                    [key]: value
                }), {}));
const saStringValue = JSON.stringify(saValue);

Dominik · Accepted Answer · 2020-07-29 22:53:36Z

1

I think this should work and make it easier.

const saResponse = {
    0: {severity: "Low", assignee: null, notesType: "Type1", notes: "Notes1", createdAt: "2020-07-29"},
    1: {severity: "High", assignee: "meallhour", notesType: null, notes: "Notes1", createdAt: "2021-07-29"},
};

const saValue = Object.values(saResponse)
    .map((row) => Object
        .values(row)
        .filter(val => val)
        .join('::')
).join(',');

console.log(saValue);

edited Jul 29, 2020 at 22:53

answered Jul 29, 2020 at 22:09

Dominik

6,3239 gold badges44 silver badges63 bronze badges

Sign up to request clarification or add additional context in comments.

3 Comments

meallhour Over a year ago

Getting an error - TS2339: Property 'map' does not exist on type 'SAInterface'.

Dominik Over a year ago

Click on Run code snippet and see the console log output. If you're getting that error it means your saResponds "array object" is not an array at all. You'll have to give us the real shape before we can help you. Also this is a typescript error. You asked a Javascript question. You have to do your own types here

meallhour Over a year ago

The answer with .values(saResponse[0]) is working fine. saResponse is an object and i have updated my question accordingly. Now, in case of multiple values i want them to be separated with , Please let me know the updated answer. Thanks!!

mr__pablo · Accepted Answer · 2020-07-29 22:26:10Z

1

// i have tried this and it work, but i cannot get where you get `Details 1` string?
const object1 = {severity: "Low", assignee: null, notesType: "Type1", notes: "Notes1", 
createdAt: "2020-07-29"};

const arr = Object.values(object1);
const filtered = arr.filter( el=>( 
   el != null)
);

console.log(filtered.join('::'))

answered Jul 29, 2020 at 22:26

mr__pablo

711 silver badge2 bronze badges

Comments

Kartik Chauhan · Accepted Answer · 2020-07-29 22:49:41Z

1

From what I could deduce from your post and comments, I think the structure for the variable saResponse is this:

You have an array with only a single item in it as the length property's value is 1. The item which is in it is an object.

Now, in your case, you only have a single item but I'm posting answers for both scenarios where you've only one item and in the second one multiple items in the array. Please make suitable changes to the code-snippet below according to your needs.

let saResponse = [
    { severity: "Low", assignee: null, notesType: "Type1", notes: "Notes1", createdAt: "2020-07-29" },
    { severity: "High", assignee: 'john', notesType: null, notes: "Notes1", createdAt: "2020-06-27" }
];

// For array with only one element
let result = Object.values(saResponse[0]).filter(el => el !== null).join('::');

// For array with multiple elements
let result2 = saResponse.map(obj => Object.values(obj).filter(el => el !== null).join('::'))

Also, I've tested the value only against null as you specifically mentioned you didn't want null values. However, I'm not sure if you have a good idea about falsy values because among many falsy values in javascript, null is one of them. Other falsy values are undefined, 0, ""(empty string), false etc. Please read this if you want more information on this.

If you don't want any falsy values then you could simply replace .filter(el => el !== null) with .filter(el => el).

edited Jul 29, 2020 at 22:49

answered Jul 29, 2020 at 22:03

Kartik Chauhan

3,1087 gold badges31 silver badges42 bronze badges

10 Comments

meallhour Over a year ago

I am getting [object Object] when trying to do console.log(result)

Kartik Chauhan Over a year ago

For the answer that I posted, I'm getting the result "Low::Type1::Notes1::2020-07-29" which looks correct to me. Please note, in my code-snippet, "saResponse" is an object and not an array. And I addressed my confusion in the answer regarding this.

meallhour Over a year ago

When i check details for saResponse, I see below

Array(1) 0: {severity: "Low", assignee: null, notesType: "Type1", notes: "Notes1", createdAt: "2020-07-29"} length: 1 __proto__: Array(0)

meallhour Over a year ago

I am getting an error - Getting an error - TS2339: Property 'map' does not exist on type 'SAInterface'.

meallhour Over a year ago

This is working fine - const saValue = Object.values(saResponse[0]).filter(val => val) .join('::'); But, how to address multiple elements using above?

|

Collectives™ on Stack Overflow

How to fetch only the values from an object ignoring the null values in NodeJS?

Desired Output

3 Answers 3

3 Comments

Comments

10 Comments

Your Answer

Hot Network Questions

Collectives™ on Stack Overflow

Desired Output

3 Answers 3

3 Comments

Comments

10 Comments

Your Answer

Sign up or log in

Post as a guest

Related