Can C struct assignment use brace syntax? [duplicate]

Question

Possible Duplicate:
Struct initialization of the C/C++ programming language?

I'm re-learning C and asking myself if something like this is possible:

typedef struct Link {
    struct Node a;
    struct Node b;
    float weight;
    } Link;

Link links[LINK_NUMBER];
links[0] = {nodes[0], nodes[1], 5};

instead of:

Link link0 = {nodes[0], nodes[1], 5};
links[0] = link;

@Juliano: I found the solution in this topic - see below. Thank you! — xyz-123
– xyz-123, Commented Jun 11, 2011 at 18:09

xyz-123 · Accepted Answer · 2011-06-11 18:07:55Z

5

that's what I was searching for:

links[0] = (Link) {nodes[0], nodes[1], 5};

answered Jun 11, 2011 at 18:07

xyz-123

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1 Comment

Juliano Over a year ago

Note that this is only valid in C99 and GNU C. Many legacy compilers will not understand this syntax. I mentioned this in the original question this one is a duplicate of.

user2100815 · Accepted Answer · 2011-06-11 17:40:54Z

1

Are you asking if structs can be assigned? If so, the answer is yes.

answered Jun 11, 2011 at 17:40

user2100815

1 Comment

xyz-123 Over a year ago

the question was actually if it is possible to use the brace syntax in assignments.

user541686 · Accepted Answer · 2011-06-11 17:40:41Z

-1

That doesn't work because a Link can't contain another Link.

However, it can contain a pointer to another Link (a Link*).

Regarding the assignment: You can only use the brace syntax when initializing a value, not when setting a value. (I believe this changes in C++0x/C++11, though.)

answered Jun 11, 2011 at 17:40

user541686

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1 Comment

David Given Over a year ago

C99 supports structure literals, which can be used in assignments.

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