javascript sub-objects and definition patterns

Question

I have been mauling over this for while now, and wonder if anyone could point me in the right direction.

I have the following object definition:

var foo=function(){};
foo.prototype={
  foo1:function(){},
  baz:{
    baz1:function(){}
  },
  bar:function(){
    function privateFunc1(){}
    function privateFunc2(){}
    return {
      bar1:function(){
        //do something using privateFunc1
        //return the result
      }
    };
  }
};

var foobar = new foo();

Now, to access the baz1 sub-method of the baz method, I can do foobar.baz.baz1()
But to access the bar1 sub-method of the bar method, I have to do foobar.bar().bar1() (Notice the extra parens after bar)

Is there a way of defining the foo object so that I can call bar1 using foobar.bar.bar1() (Notice, no extra parens), But still keep the use of private functions privateFunc1 and privateFunc2 within the bar method.

Also, please note that I cannot make bar a self-executing function because it depends on mutable properties of the foo object, which may change after the function has self-executed.

Hope the question was clear enough... thanks in advance.

bbg · Accepted Answer · 2011-06-12 03:24:14Z

2

This might be going in the direction you want. http://jsfiddle.net/Una9k/1/

var Foo = function() {
    this.mutableProperty = "mutable";
    this.bar = new Foo.prototype.Bar(this);
};
Foo.prototype = {
    constructor: Foo,
    Bar:function(context){
        var ctx = context;
        function privateFunc(){
            alert(ctx.mutableProperty);
        }
        return {
            bar1: function () {
                privateFunc();    
            }
        };
    }
};

var foobar = new Foo();
foobar.bar.bar1(); // alerts 'mutable'

foobar.mutableProperty = "changed";
foobar.bar.bar1(); // alerts 'changed'

answered Jun 12, 2011 at 3:24

bbg

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Comments

MillsJROSS · Accepted Answer · 2011-06-12 02:52:11Z

Perhaps this might work...

function createFooBar() {
   //return foobar   
   var foobar = {
      foo1: function() {},
      baz: {
          baz1: function(){}
      },
      bar: function(){
          function privateFunc1(){}
          function privateFunc2(){}
          return {
              bar1:function(){
                 //do something using privateFunc1
                 //return the result
              }
          }
      }
   };

   foobar.bar.bar1 = foobar.bar();

   return foobar;
};

var foobar = createFoobar();

Using the above you could also house your functions on the createFooBar function. So after the above...

createFooBar.foo1 = function(){} //and so on...

then in the createFooBar function you might refer to foo1 like so...

//code in the beginning...
var foobar = {
    foo1: createFooBar.foo1,
//and so on...

Additionally, you could ALSO just create a create function on your current foo function...

foo.create = function() {
    var fooBar = new Foo();
    fooBar.bar.bar1 = fooBar.bar();
    return fooBar;
}

var fooBar = foo.create();

James · Accepted Answer · 2011-06-12 02:57:57Z

1

If it is possible to call foobar.bar() immediately:

function createFooBar() {
   //return foobar   
   var foobar = {
      foo1: function() {},
      baz: {
          baz1: function(){}
      },
      bar: function(){
          function privateFunc1(){}
          function privateFunc2(){}
          return {
              bar1:function(){
                 //do something using privateFunc1
                 //return the result
              }
          }
      }()
   };


   return foobar;
};
// now you have foobar.bar.bar1()

answered Jun 12, 2011 at 2:57

James

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1 Comment

ekhaled Over a year ago

can't self-execute the function because it depends on mutable properties of the object.

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