Looping numbers with object values and push output to a array

Question

This is for a line chart. Some values are available in the object "filteredTime" and need to fill "0" for unavailable values in the object.

for loop match with object values and push the output to the selected array. Object number of items are dynamic.

Expected outcome is 10 items Array. My output is 20 items array according to 2items in the object. Solution required for dynamic number of items in the object when looping.

let dataa = {
  datasets: [{ data: [] }],
};

let filteredTime = { 4: "13.50", 7: "12.50" };

for (let step = 1; step <= 10; step++) {
  for (var i in filteredTime) {
    if (step != i) {
      dataa["datasets"].map((filteredPerson) => {
        filteredPerson.data.push(0);
      });
    } else {
      dataa["datasets"].map((filteredPerson) => {
        filteredPerson.data.push(filteredTime[i]);
      });
    }
  }
}

Output

Array(20): [0, 0, 0, 0, 0, 0, 0, "12.50", 0, 0, 0, 0, "13.50", 0, 0, 0, 0, 0, 0, 0]

"filteredTime" Object items number are dynamic.

Expected Output:

Array(10): [0, 0, 0, "12.50", 0, 0, "13.50", 0, 0, 0, ]

User863 · Accepted Answer · 2020-08-02 13:42:56Z

1

Using Array.from()

let filteredTime = { 4: "13.50", 7: "12.50" }

let result = Array.from({length: 10}, (v, i) => filteredTime[i + 1] || 0)

console.log(result)

answered Aug 2, 2020 at 13:42

User863

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Comments

Dharman · Accepted Answer · 2020-08-02 13:48:06Z

0

let dataa = {
  datasets: [{ data: [] }],
};

let filteredTime = { 4: "13.50", 7: "12.50" };

  for(let i=1;i<=10;i+=1){
    if(!filteredTime[i]){
      dataa.datasets[0].data.push(0)
   }else{
      dataa.datasets[0].data.push(filteredTime[i])
  }

}

edited Aug 2, 2020 at 13:48

Dharman♦

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answered Aug 2, 2020 at 13:42

Rajesh Kumaran

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