How to get GET params from express with typescript in node.js?

Question

Im using node.js + express + typescript, and I want to get GET params. I have this so far

app.get('/top_games', (req, res) => {
    const page = req.route.page;
    const offset = req.route.offset;
    const game_data = DAO_GAME.GetTopGuilds(100, 0);
    res.send({
        total : game_data[0],
        data : game_data[1]
    });
});

but the eslint complains for

    const page = req.route.page;
    const offset = req.route.offset;

saying

Unsafe assignment of an any value.eslint@typescript-eslint/no-unsafe-assignment
Unsafe member access .page on an any value.eslint@typescript-eslint/no-unsafe-member-access

How can I fix this?

What does req.params give you? app.get('/user/:id', function (req, res) { res.send('user ' + req.params.id) }) — arunmmanoharan
– arunmmanoharan, Commented Aug 10, 2020 at 2:39

omega · Accepted Answer · 2020-08-10 02:49:13Z

1

Fixed it, I had to do

const page = parseInt(req.query.page as string, 10);
const page_size = parseInt(req.query.page_size as string, 10);

answered Aug 10, 2020 at 2:49

omega

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Tholle · Accepted Answer · 2020-12-09 19:30:16Z

1

As of @types/[email protected], the Request type uses generics. We can use this to type the parsed query parameters ourselves:

import { Request } from 'express';

type QueryParams = {
    page: string;
    page_size: string;
};

app.get('/top_games', (req: Request<{}, {}, {}, QueryParams>, res) => {
    const page = parseInt(req.route.page, 10);
    const offset = parseInt(req.route.offset, 10);

    // ...
});

answered Dec 9, 2020 at 19:30

Tholle

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1 Comment

JoelinRome Over a year ago

Thank you for answering this, I've just spent the last few days trying to figure this out and this is exactly what I was looking for

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