Create a string from a list using list comprehension

Question

I am trying to create a string separated by comma from the below given list

 ['D:\\abc\\pqr\\123\\aaa.xlsx', 'D:\\abc\\pqr\\123\\bbb.xlsx', 'D:\\abc\\pqr\\123\\ccc.xlsx']

New string should contain only the filename like below which is separated by comma

'aaa.xlsx,bbb.xlsx,ccc.xlsx'

I have achieved this using the below code

n = []        
for p in input_list:
    l = p.split('\\')
    l = l[len(l)-1]
    n.append(l)
a = ','.join(n)
print(a)

But instead of using multiple lines of code i would like to achieve this in single line using a list comprehension or regular expression.

Thanks in advance...

Inder · Accepted Answer · 2020-08-10 11:04:26Z

5

Simply do a

main_list = ['D:\\abc\\pqr\\123\\aaa.xlsx', 'D:\\abc\\pqr\\123\\bbb.xlsx', 'D:\\abc\\pqr\\123\\ccc.xlsx']

print([x.split("\\")[-1] for x in main_list])

OUTPUT:

['aaa.xlsx', 'bbb.xlsx', 'ccc.xlsx']

In case u want to get the string of this simply do a

print(",".join([x.split("\\")[-1] for x in main_list]))

OUTPUT:

aaa.xlsx,bbb.xlsx,ccc.xlsx

Another way to do the same is:

print(",".join(map(lambda x : x.split("\\")[-1],main_list)))

OUTPUT:

aaa.xlsx,bbb.xlsx,ccc.xlsx

Do see that os.path.basename is OS-dependent and may create problems on cross-platform scripts.

edited Aug 10, 2020 at 11:04

answered Aug 10, 2020 at 10:46

Inder

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Comments

Rakesh · Accepted Answer · 2020-08-10 10:41:38Z

2

Using os.path.basename with str.join

Ex:

import os
data = ['D:\\abc\\pqr\\123\\aaa.xlsx', 'D:\\abc\\pqr\\123\\bbb.xlsx', 'D:\\abc\\pqr\\123\\ccc.xlsx']
print(",".join(os.path.basename(i) for i in data))

Output:

aaa.xlsx,bbb.xlsx,ccc.xlsx

answered Aug 10, 2020 at 10:41

Rakesh

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