How to Serialize pattern matched XML elements into a List using C#

Question

I have an XML input as follows-

<?xml version="1.0"?>
-<INPUT>
   <V0>10.0000</V0>
   <V1>20.0000</V1> 
   <V2>30.0000</V2>
   <V3>:0.0000</V3>
   <V4>30.0000</V4>
   <V5>0.0000</V5>
   <V6>0.0000</V6>
   <V7>0.0000</V7>
   <V8>0.0000</V8>
   <V9>0.0000</V9>
   <V10>0.0000</V10>
   <V11>50.0000</V11>
   <V12>20.0000</V12>
   <V13>60.0000</V13>
   <V14>30.0000</V14>
   <V15>0.0000</V15>
   <V16>1.0000</V16>
-</INPUT>

I want to serialize it to an object for the following C# class structure-

class Input 
{
  List<V> variables; 
}

So I want to create a list for the XML elements which has pattern V[0-9]+ (e.g V0, V1, V2 and so on). The list is an ordered list to preserve the index of the variable elements. Just to mention if we can successfully serialize the mentioned XML as expected then the object should have a list of 16 items(since there are 16 XML elements with pattern V[0-9]+). The actual XML input has few hundreds variable elements.

Sounds to me like the OP wants to read the XML data into dynamic (I think the V is meant as a generic here), and put it in a list with variable names same as the XML element names? — Sach
– Sach, Commented Aug 11, 2020 at 18:28
This is probably what you're looking for stackoverflow.com/a/39902334/302248 — Sach
– Sach, Commented Aug 11, 2020 at 18:30
V class can be just a simple class with a string field only. — Satyajit Dey
– Satyajit Dey, Commented Aug 11, 2020 at 18:51
You will need to subclass List<decimal> (or Collection<decimal> if you prefer) and implement IXmlSerializable. For how, see How do you deserialize XML with dynamic element names?. In fact this may be a duplicate, agree? — dbc
– dbc, Commented Aug 11, 2020 at 21:41

jdweng · Accepted Answer · 2020-08-12 01:15:11Z

1

Use xml linq :

using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
using System.Xml;
using System.Xml.Linq;

namespace ConsoleApplication1
{
    class Program
    {
        const string FILENAME = @"c:\temp\test.xml";
        static void Main(string[] args)
        {
            Input input = new Input();
            XDocument doc = XDocument.Load(FILENAME);
            input.variables = doc.Element("INPUT").Elements().Select(x => decimal.Parse((string)x)).ToList();

        }

    }
    public class Input
    {
        public List<decimal> variables;
    }
}

answered Aug 12, 2020 at 1:15

jdweng

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