Python separate matching string at the end of a string

Question

I'm finding it difficult getting started with regular expressions in python.

I have a bunch of strings now that look like this:

<street address><SPACE><#><SPACE><Suite number or letter>

I need to separate the Suite number from the rest of the string and save it in another variable. I also need a copy of the street address without the suite number.

Here are some examples:

    1111 19th St NW # 200
    1408 U St NW # A
    1509 17th St NW # 1
    1515 14th St NW # 1
    1612 K St NW # 1000
    1700 17th St NW # C
    1900 K St NW # 1200
    1900 M St NW # 200
    6034 Baltimore Ave # 2
    843 Quarry Road # 140
    8455 Colesville Rd # 100

What is a good way to do this?

Thanks!

Demian Brecht · Accepted Answer · 2011-06-13 22:02:36Z

2

Something like this work for you?

s = '1111 19th St NW # 200'
n = s.split('#')[1].strip()

print n

http://ideone.com/OnaqX

answered Jun 13, 2011 at 22:02

Demian Brecht

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Daniel DiPaolo · Accepted Answer · 2011-06-13 22:01:45Z

2

s.split()[-1]

This will return the entirety of the string after the last space.

With a few of your strings as examples:

>>> L = ["1111 19th St NW # 200",
    "1408 U St NW # A",
    "1509 17th St NW # 1",
    "1515 14th St NW # 1"]
>>> [s.split()[-1] for s in L]
['200', 'A', '1', '1']

answered Jun 13, 2011 at 22:01

Daniel DiPaolo

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Justin Morgan · Accepted Answer · 2011-06-13 22:03:03Z

2

Well, I'm not sure how variable your input can be, but either one of these patterns would grab the suite numbers from the examples you gave:

/\w+$/

/\#\s*(\w+)/

answered Jun 13, 2011 at 22:03

Justin Morgan

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