multiple option echo php & mysql

Question

how can i output more when 1 array. when i delete , ["nr"] evrything works. but i need the second one too...

<div>
      <select name="name[]">
           <option value = ""> Select the person with phone nbr. </option>
           <?php foreach ($results as $output) {?>

           <option> <?php echo $output ["fname"],["nr"]; ?> </option>

      <?php } ?>
      </select>
 </div>

What is the expected HTML output? Also, this seems prone to XSS. — D. Pardal
– D. Pardal, Commented Aug 12, 2020 at 16:04
<option value="SOME_VALUE"> <?php echo $output ["fname"].",".["nr"]; ?> </option> — my_workbench
– my_workbench, Commented Aug 12, 2020 at 16:05

Airful · Accepted Answer · 2020-08-12 16:28:16Z

1

does "nr" is an index of $output array? if so, then you have to write it like this:

<?php echo $output["fname"]  . "," . $output["nr"]; ?>

answered Aug 12, 2020 at 16:28

Airful

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1 Comment

Airful Over a year ago

@whoamiidontknowit can you please accept the answer as solution? :)

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