Skip exceptions in python

Question

I have a newbie questions: let say I have this list of stock in python

import requests

list = ["AMZN","APPL", "BAC"]

try:
    for x in list:
        url ='https://financialmodelingprep.com/api/v3/quote-short/'+x+'?apikey=demo'
        response = requests.request('GET', url)
        result = response.json()
        print(result[0]["price"]) 

except:
    pass

the second ticker will throw an exceptions, how do I make python to run the third ticker no matter what happen to the second ticker requests?

A blanket except is almost always a bug. See stackoverflow.com/questions/21553327/… — tripleee
– tripleee, Commented Aug 13, 2020 at 8:00

Sociopath · Accepted Answer · 2020-08-13 07:52:56Z

1

Use try-except inside for loop like below

import requests

list = ["AMZN","APPL", "BAC"]


for x in list:
    try:
        url ='https://financialmodelingprep.com/api/v3/quote-short/'+x+'?apikey=demo'
        response = requests.request('GET', url)
        result = response.json()
        print(result[0]["price"]) 

    except:
       pass

answered Aug 13, 2020 at 7:52

Sociopath

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Comments

Ahmet · Accepted Answer · 2020-08-13 07:52:09Z

0

You can use continue

import requests

list = ["AMZN","APPL", "BAC"]

for x in list:
    try:
        url ='https://financialmodelingprep.com/api/v3/quote-short/'+x+'?apikey=demo'
        response = requests.request('GET', url)
        result = response.json()
        print(result[0]["price"])
    except:
        continue

answered Aug 13, 2020 at 7:52

Ahmet

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