Get Date value from object property - javascript

Question

How can i get only the Date without the string value from below object?

0: {2020-09-02: "string_1", 2020-09-03: "string_2"}
1: {2020-09-01: "string_1", 2020-09-05: "string_2"}

My objective is to get the Date only and group them into one array.

Expected result: [2020-09-02, 2020-09-03, 2020-09-01, 2020-09-05]

What I tried so far is using Object.getOwnPropertyNames:

console.log('property name: ', Object.getOwnPropertyNames(getDateProperties)) // return ["0","1"]

Is this something possible to achieve?

yes did tried it before but result is similar which return, ["0", "1"] @Asutosh — 1aliff
– 1aliff, Commented Aug 16, 2020 at 11:54
are you sure your data is an Object and not an Array of objects? — Roko C. Buljan
– Roko C. Buljan, Commented Aug 16, 2020 at 11:56
@1aliff I have posted the answer using Object.keys. Please have a look. — Asutosh
– Asutosh, Commented Aug 16, 2020 at 11:59

EugenSunic · Accepted Answer · 2020-08-16 11:54:26Z

1

Use reduce and Object keys to get the dates from the object

const list = [{
    "2020-09-02": "string_1",
    "2020-09-03": "string_2"
  },
  {
    "2020-09-01": "string_1",
    "2020-09-05": "string_2"
  }
]
const result = list.reduce((acc, x) => {
  const keys = Object.keys(x)
  acc = [...acc, ...keys]
  return acc;
}, [])
console.log(result)

answered Aug 16, 2020 at 11:54

EugenSunic

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Comments

Majed Badawi · Accepted Answer · 2020-08-16 11:55:06Z

1

Try this:

let obj = {
0: {"2020-09-02": "string_1", "2020-09-03": "string_2"},
1: {"2020-09-01": "string_1", "2020-09-05": "string_2"}
}
let arr = [];
for(var key in obj){
    for(var subkey in obj[key]){
        arr.push(subkey);
    }
}
console.log('property name: ', arr)

answered Aug 16, 2020 at 11:55

Majed Badawi

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Comments

Asutosh · Accepted Answer · 2020-08-16 11:58:24Z

1

You may try like this:

let obj = {
  0: {
    "2020-09-02": "string_1",
    "2020-09-03": "string_2"
  },
  1: {
    "2020-09-01": "string_1",
    "2020-09-05": "string_2"
  }
}
const resultArray = [];
Object.keys(obj).forEach((k) => Object.keys(obj[k]).forEach((dateArg) => resultArray.push(dateArg)));
console.log(resultArray);

answered Aug 16, 2020 at 11:58

Asutosh

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Comments

Eugene Karakulin · Accepted Answer · 2020-08-16 12:08:55Z

0

Quick one-liner

let obj = {
    0: {"2020-09-02": "string_1", "2020-09-03": "string_2"},
    1: {"2020-09-01": "string_1", "2020-09-05": "string_2"}
}

let output = Object.keys(obj).reduce((acc, key) => [...acc, ...Object.keys(obj[key])], [])

console.log(output)

answered Aug 16, 2020 at 12:08

Eugene Karakulin

1

Comments

Siva Kondapi Venkata · Accepted Answer · 2020-08-16 12:20:35Z

0

Use flatMap and Object.keys should simplify

const list = [
  {
    "2020-09-02": "string_1",
    "2020-09-03": "string_2",
  },
  {
    "2020-09-01": "string_1",
    "2020-09-05": "string_2",
  },
];

const res = list.flatMap(Object.keys);

console.log(res);

Alternatively, if the input data is object.

let obj = {
  0: {
    "2020-09-02": "string_1",
    "2020-09-03": "string_2"
  },
  1: {
    "2020-09-01": "string_1",
    "2020-09-05": "string_2"
  }
}

const res = Object.values(obj).flatMap(Object.keys);

console.log(res)

answered Aug 16, 2020 at 12:20

Siva Kondapi Venkata

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