ruby add strings from array

Question

I am building a simple breadcrumb in ruby but I am not sure how to really implement my logic.

Let's say I have an array of words that are taken from my request.path.split("/) ["", "products", "women", "dresses"] I want to push the strings into another array so then in the end I have ["/", "/products", "products/women", "products/women/dresses"] and I will use it as my breadcrumb solution.

I am not good at ruby but for now I came up with following

cur_path = request.path.split('/')

cur_path.each do |link|
  arr = []
  final_link = '/'+ link
  if cur_path.find_index(link) > 1
    # add all the previous array items with the exception of the index 0
  else
    arr.push(final_link)
  end
end

The results should be ["/", "/products", "/products/women", "/products/women/dresses"]

Stefan · Accepted Answer · 2020-08-24 10:04:22Z

6

Ruby's Pathname has some string-based path manipulation utilities, e.g. ascend:

require 'pathname'

Pathname.new('/products/women/dresses').ascend.map(&:to_s).reverse
#=> ["/", "/products", "/products/women", "/products/women/dresses"]

answered Aug 24, 2020 at 10:04

Stefan

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Comments

eikes · Accepted Answer · 2020-08-24 09:02:47Z

3

This is my simplest solution:

a = '/products/women/dresses'.split('/')
a.each_with_index.map { |e,i| e.empty? ? '/' : a[0..i].join('/')  }

answered Aug 24, 2020 at 9:02

eikes

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Comments

Yakov · Accepted Answer · 2020-08-24 09:20:37Z

2

Using map and with_index it can be done like this:

arr = ["", "products", "women", "dresses"]
arr.map.with_index { |item, index| "#{arr[0...index].join('/')}/#{item}" }

answered Aug 24, 2020 at 9:20

Yakov

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Comments

iGian · Accepted Answer · 2020-08-24 09:38:06Z

2

This is another option using Enumerable#each_with_object and Enumerable#each_with_index:

ary = '/products/women/dresses'.split('/')
ary[1..].map
        .with_index
        .with_object([]) { |(folder, idx), path| path << [path[idx-1], folder].join('/') }.unshift('/')

Or also:

(ary.size - 1).times.map { |i| ary.first(i + 2).join('/') }.unshift('/')

edited Aug 24, 2020 at 9:38

answered Aug 24, 2020 at 9:17

iGian

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