I want to check if objects within an array is empty or not. This is how I receive my data and the object length is dynamic so I cannot use any hard coded condition.
[{},{},{},{},{},{},{},{},{},{}] // length is dynamic
I have ways liek:
Object.keys(myarray[0]).length === 0; //but this applies only for object.
is there an elegant way of checking this in one condition by any chance?
To detect if there are any empty objects in your array, use Array.prototype.some() combined with Object.keys() and Array.prototype.length
const anyEmptyObjects = myarray.some(o => Object.keys(o).length === 0)
To retrieve the empty objects, use the same predicate with Array.prototype.filter()
const emptyObjects = myarray.filter(o => Object.keys(o).length === 0)
What about Object.entries? Though I suppose that's not much different
let a = [{},{test:1},{},{},{test:2},{},{},{test:3},{},{}];
let result = a.map((ele) => (Object.entries(ele) == 0));
output
[true, false, true, true, false, true, true, false, true, true]
To complete @jmp 's solution you can get the final answer of hasEmapty like this:
const hasEmpty = arr => arr.reduce((acc, obj)=> acc || !Object.entries(obj).length, false)
//---
let a = [{},{test:1},{},{},{test:2},{},{},{test:3},{},{}];
let b = [{test: 3}, {test: 4}, {test: 5}]
let c = [{},{}]
let d = []
console.log(hasEmpty(a))
console.log(hasEmpty(b))
console.log(hasEmpty(c))
console.log(hasEmpty(d))
