#include <iostream>
#include <iomanip>
#include <string>
#include <algorithm>
using namespace std;
void getinput (string &first,string &second);
void lengthcheck (string first, string second);
//int anagramcheck (string word);
int* lettercounter (string input);
int main()
{
std::string a;
std::string b;
getinput(a,b);
lengthcheck (a,b);
lettercounter(a);
lettercounter(b);
int* one = lettercounter(a);
int* two = lettercounter(b);
if (one == two)
cout << "You Have Entered An Anagram" << endl;
else
cout << "You Have Not Entered An Anagram" << endl;
}
void getinput (string &first, string &second) {
cout << "Enter First Input: ";
getline(cin, first, '\n');
cout << "Enter Second Input: ";
getline(cin, second, '\n');
cout << "You Entered " << first << " and " << second <<endl;
}
void lengthcheck(string first, string second){
int lengtha = first.length();
int lengthb = second.length();
if ((lengthb > 60) || (lengtha > 60)) {
cout << "Input Is Invalid" << endl;
} else if (lengtha !=lengthb) {
cout << "Input is not an anagram" << endl;
} else {
cout << "Input is Valid" << endl;
}
}
int* lettercounter(string input)
{
static int freq[26] = {0};
int length = input.length();
for (int i=0; i<26; i++) {
freq[i]=0;
}
for (int i=0; i <length; i++) {
if(input[i]>='a' && input[i]<='z')
{
freq[input[i] - 97]++;
}
else if(input[i]>='A' && input[i]<='Z')
{
freq[input[i] - 65]++;
}
}
for(int i=0; i<26; i++) {
/* If current character exists in given string */
if(freq[i] != 0)
{
printf("'%c' = %d\n", (i + 97), freq[i]);
}
return freq;
}
}
I am having trouble returning the array named freq from the user definied function called lettercount. Can someone give me a hint? I need the lettercount to return an array. I need to call the function lettercount twice so i can compare the results of each array to determine if the two inputs are anagrams. I am not sure if the function is returning an actual value to the main.
vectorinstead.return freq;INSIDE yourforloop?