syntax error on python 3.x with variables

Question

so I tried to list some variables and I keep getting a syntax error.

usr1 = 'boy'
usr2 = 'girl'
usr = input("What's your username: ")
if usr != usr1, usr2:
   print('Username not found, try again')

then I get an error

if usr != usr1, usr2:
              ^
SyntaxError: invalid syntax

I also tried to remove the commas, same error, thanks

Barmar · Accepted Answer · 2020-09-04 04:48:23Z

1

You can't compare with two variables like that. You need to do two separate comparisons and combine them with a logical operation.

if usr != usr1 and usr != usr2:

Or you can put all your usernames in a collection:

valid_users = {usr1, usr2}
if usr not in valid_users:

answered Sep 4, 2020 at 4:48

Barmar

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Comments

Aryan · Accepted Answer · 2020-09-04 04:49:03Z

0

This snippet might solve your question

usr1 = 'boy'
usr2 = 'girl'
usr = input("What's your username: ")
if usr != usr1 and usr != usr2:
    print('Username not found, try again')

answered Sep 4, 2020 at 4:49

Aryan

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Janith · Accepted Answer · 2020-09-04 05:22:32Z

0

usr1 = 'boy'
usr2 = 'girl'
usr = input("What's your username: ")
if usr not in [usr1, usr2]:
   print('Username not found, try again')

Or you can use

usr1 = 'boy'
usr2 = 'girl'
usr = input("What's your username: ")
if usr!=usr1 and usr!=usr2:
   print('Username not found, try again')

answered Sep 4, 2020 at 5:22

Janith

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