How to send query value without URL encoding in go-lang?

Question

Example:

package main

import (
    "fmt"
    "log"
    "net/url"
)

func main() {
    u, err := url.Parse("http://bing.com/search?q=dotnet")
    if err != nil {
        log.Fatal(err)
    }
    u.Scheme = "https"
    u.Host = "google.com"
    q := u.Query()
    q.Set("q", "golang../")
    u.RawQuery = q.Encode()
    fmt.Println(u)
}

Output: https://google.com/search?q=golang..%2F here "/" is encoded to "%2F" what to do if we don't what this and want something like https://google.com/search?q=golang../ I tried to find a lot on google but didn't get anything

%2F didn't work as intended if manually put "/" it works as intended — KATHAN PATEL
– KATHAN PATEL, Commented Sep 13, 2020 at 17:07

KATHAN PATEL · Accepted Answer · 2020-09-13 17:08:33Z

5

So I Found an Answer to this here the code

package main

import (
    "fmt"
    "log"
    "net/url"
)

func main() {
    u, err := url.Parse("http://bing.com/search?q=dotnet")
    if err != nil {
        log.Fatal(err)
    }
    u.Scheme = "https"
    u.Host = "google.com"
    q := u.Query()
    q.Set("q", "golang../")
    u.RawQuery = q.Encode()
    decoded,err:=url.QueryUnescape(q.Encode())
    u.RawQuery= decoded
    if err != nil {
        return
    } 
    fmt.Println(u)
}

had to use url.QueryUnescape

answered Sep 13, 2020 at 17:08

KATHAN PATEL

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Comments

Burak Serdar · Accepted Answer · 2020-09-13 17:05:39Z

3

Set the raw query to what you need, not to the encoded value:

u, err := url.Parse("http://bing.com/search?q=dotnet")
if err != nil {
   log.Fatal(err)
}
u.Scheme = "https"
u.Host = "google.com"
u.RawQuery = fmt.Sprintf("q=golang../")
fmt.Println(u)

answered Sep 13, 2020 at 17:05

Burak Serdar

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1 Comment

KATHAN PATEL Over a year ago

the above code is just an example for the same code I used in my main code and I have undefined params but defined payloads which I need to send as a value in those query params. so this solution is not applicable.

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