Python: Print repeated value in a string

Question

I have to write a simple program in python 3.6 that takes the user input and computes the value of n+n*n+n*n*n+n*n*n*n.

So if the user enters 7, then the following should be printed to the console 7+7*7+7*7*7+7*7*7*7 = 2800.

How do i accomplish this with the print function?

So far i have tried the following:

input_int = int(input("Please enter a value: "))

result_int = input_int + input_int * input_int + input_int * input_int * input_int +  input_int * input_int * input_int * input_int

print(input_int + input_int * input_int + input_int * input_int * input_int +  input_int * input_int * input_int * input_int, " = ", result_int)

and doesn't give me what i want.

You can use convert the input_int to string, and use + to concatenate them. — 21rw
– 21rw, Commented Sep 20, 2020 at 3:28
Please show more context. Where does input_int come from? Where is your calculation for result_int? — Karl Knechtel
– Karl Knechtel, Commented Sep 20, 2020 at 3:29
Anyway, of course it doesn't give you what you want - there is nothing in your code, for example, that attempts to produce + or * symbols in the output. Think through the steps of the problem logically. — Karl Knechtel
– Karl Knechtel, Commented Sep 20, 2020 at 3:30

ADEREMI ADESADA · Accepted Answer · 2020-09-20 03:53:32Z

2

input_int = int(input("Please enter a value: "))
result_int = input_int + input_int * input_int + input_int * input_int * input_int +  input_int * input_int * input_int * input_int
input_string = f'{input_int} + {input_int} * {input_int} + {input_int} * {input_int} + {input_int} * {input_int} + {input_int} * {input_int} + {input_int} = {result_int}'

print(input_string)

edited Sep 20, 2020 at 3:53

answered Sep 20, 2020 at 3:48

ADEREMI ADESADA

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Comments

AirSquid · Accepted Answer · 2020-09-20 03:33:16Z

1

Here is a bit of help as this seems like a H/W assignment.

You need to convert the integers into strings and handle the math symbols as strings... So something like this...

In [2]: my_int = 7                                                              

In [3]: # convert to a string...                                                

In [4]: my_int = str(my_int)                                                    

In [5]: print(my_int,'+',my_int,'*')                                            
7 + 7 *

answered Sep 20, 2020 at 3:33

AirSquid

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Comments

Naman · Accepted Answer · 2020-09-20 03:36:48Z

1

Considering your result is already stored in result_int, and the 'n' is stored in input_int.

print(input_int + input_int * input_int + input_int * input_int * input_int + input_int * input_int * input_int * input_int, " = ",result_int)

This wouldn't work, as you are directly printing the value.

You need to use something like:

print(input_int + '+' + input_int + '*' + input_int + '+' + input_int + '*' + input_int + '*' + input_int + '+' + input_int + '*' + input_int + '*' + input_int + '*' + input_int, " = ",result_int)

This would give the desired output.

answered Sep 20, 2020 at 3:36

Naman

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2 Comments

CrazyCoder Over a year ago

Or can we use a for loop to print this iteratively?

Naman Over a year ago

Yes, we can use the for loop for it also.

Bipul singh kashyap · Accepted Answer · 2020-09-20 04:29:20Z

If the number of iteration is fixed to 4 then you can iterate from 1 to 5 or if your iteration is dynamic you can replace 5 with your variable.

input_int = int(input("Please enter a value: "))
out = 0
string = ''
for i in range(1,5):
    string += (str(input_int)+"*")*i+"+"
    out += pow(input_int, i)

string = string.replace("*+", " + ")[:-2]+" = "

print(string+str(out))

Explain:

for is iterating from 1 to 5 which results in 4 times iteration.

string += (str(input_int)+"")i+"+" which will create a string display like 7 + 77+ 777*+

Here extra '*' and '+' sign need to be removed.

out += pow(input_int, i)

Pow is the default python function to calculate the square of a number like pow(7,2)

Replace extra '*' and '+' with replace and add '=' at the end.

user3657941 · Accepted Answer · 2020-09-20 04:33:54Z

1

After reading the latest comments, I think you are looking for something like this:

x = 7
result = 7 + (7 * 7) + (7 * 7 * 7) + (7 * 7 * 7 * 7)
print(f'{x} + {x} * {x} + {x} * {x} * {x} + {x} * {x} * {x} * {x} = {result}')

Output

7 + 7 * 7 + 7 * 7 * 7 + 7 * 7 * 7 * 7 = 2800

Python Documentation: Formatted String Literals (f-strings)

answered Sep 20, 2020 at 4:33

user3657941

Comments

Kelly Bundy · Accepted Answer · 2020-09-20 04:27:31Z

0

Just a little math.

>>> n = 7
>>> (n**5 - 1) // (n - 1) - 1
2800

answered Sep 20, 2020 at 4:27

Kelly Bundy

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