Why does this not remove the http:// of the string?
$rurl = 'http://www.google.com';
$httpposi = strpos($rurl,'://');
echo $httpposi;
if($httpposi === true) {
$url=substr($rurl, strpos($rurl, '://') + 3);
echo $url;
} else {
$url=$rurl;
echo '3'.$url.'2';
}
echo $url;
Instead of:
if($httpposi === true) {
you need:
if($httpposi !== false) {
since if it is found in the string, it will return an offset as an integer, and you are doing a strict comparison and strictly an non-zero, positive integer is not equal to the boolean value true.
8 == true // true
8 === true // false, because 8 is not a boolean
0 == true // false, but we need to know if the needle is at position 0
so:
0 !== false // true, string was found
8 !== false // true, string was found
false !== false // false, string was not found
If the sequence is found at the beginning of the string, the falsy 0 will be returned, thus the need to strictly compare to false to know that it has not been found at all.
As a few others already posted: Do not compare $httpposi with a boolean value! The return value of the strpos function is an integer value if it has found an occurence, but can return either false, 0 or "" if it didn't find your passed string.
For more information, take a look at the PHP.net docs!
Or you could use preg_replace instead and get rid of the problem another way:
$url=preg_replace('~^https?://~i','','http://www.google.com')
Caters for https as well. Just remove [s]? if that's not what you want. The /i is for ignoring case.
if($httpposi !== false) {
Change if($httpposi === true) { to if($httpposi) { or if($httpposi == true) {, since $httpposi = 4 isn't === to true.
