How to write foreach loop for array in php

Question

After submitting the form i am getting the array

$regData = {"student":"699","eposter":"99","exhibitor":"1199","Single-2-nights":"400"};

I need this look like this:

student : 699  
eposter : 99  
exhibitor : 1199  
Single-2-nights : 400

I am writing this like:

<?php
foreach($regData as $key => $value){  
    $selected .= $key." :". $value."<br/>";  
}  
?>

Showing error

invalid argument passed to forech

Please help me to fix this error

$regData looks more like JSON and as it stands, won't work as an array. If you had quotes round it, then try json_decode(). — Nigel Ren
– Nigel Ren, Commented Sep 23, 2020 at 12:22
Please provide your debugging attempts, and a full reproducable example. In the given snippet, $regData is undefined - where does it come from? — Nico Haase
– Nico Haase, Commented Sep 23, 2020 at 12:25
$regData = {"student":"699","eposter":"99","exhibitor":"1199","Single-2-nights":"400"}; isn't valid PHP. This can't be your real code. Please clarify. Is it actually a string like $regData = '{"student":"699","eposter":"99","exhibitor":"1199","Single-2-nights":"400"}';, perhaps? That would be valid. Then, as the first comment above says, you could decode it into an array / object and then use it easily in a loop. — ADyson
– ADyson, Commented Sep 23, 2020 at 12:26
Are looking for something like this ? sandbox.onlinephpfunctions.com/code/… — executable
– executable, Commented Sep 23, 2020 at 12:35

JPA · Accepted Answer · 2020-09-23 12:45:08Z

3

It is a JSON String, You have to decode it first using Json_decode

    $regData = '{"student":"699","eposter":"99","exhibitor":"1199","Single-2-nights":"400"}';
    $arrayData = json_decode($regData,true);
    $selected ='';
    foreach($arrayData as $key => $value){
    $selected .= $key." :". $value."<br/>";
    }

answered Sep 23, 2020 at 12:45

JPA

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Comments

dragos.nicolae · Accepted Answer · 2020-09-23 12:32:12Z

2

$regData = '{"student":"699","eposter":"99","exhibitor":"1199","Single-2-nights":"400"}';
print_r(json_decode($regData));

will result an object

answered Sep 23, 2020 at 12:32

dragos.nicolae

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1 Comment

Jay Blanchard Over a year ago

While this code may answer the question, providing additional context regarding why and/or how this code answers the question improves its long-term value. A good answer will always have an explanation of what was done and why it was done in such a manner, not only for the OP but for future visitors to SO.

Naveed Ramzan · Accepted Answer · 2020-09-23 12:25:27Z

1

$regData = ["student" => "699",
            "eposter" => "99",
            "exhibitor" => "1199",
            "Single-2-nights" => "400"];

in php, array should be in square brackets

foreach($regData as $key => $value){  
    $selected .= $key." :". $value."<br/>";  
}

Foreach code is OK.

?>

edited Sep 23, 2020 at 12:25

answered Sep 23, 2020 at 12:23

Naveed Ramzan

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2 Comments

Nigel Ren Over a year ago

In PHP, arrays also use => instead of :.

ADyson Over a year ago

@executable the OP's data isn't valid PHP, so, no-one can use that. If you see the comments on the main thread, above, you'll note that people are asking OP to clarify if it's actually meant to be a JSON string, or what. But this example here would serve a a valid sample, assuming that the data in the original question then gets decoded to a valid associative array.

Umair Malik · Accepted Answer · 2020-09-23 12:30:47Z

0

Hi Ganesh I Checked your code, your foreach loop syntax is fine but It's a better practice to write endforeach; at the end of loop + in your array replace : with =>

answered Sep 23, 2020 at 12:30

Umair Malik

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3 Comments

Nigel Ren Over a year ago

but It's a better practice to write endforeach; - where do you get this idea from?

Umair Malik Over a year ago

php.net/manual/en/control-structures.foreach.php

Nigel Ren Over a year ago

That page only mentions endforeach once and nothing in there says it's best practice

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