Laravel, how to merge Many array with array itself from foreach?

Question

when i try:

echo $response;

the output is LIKE (similiar):

{
    "identity": {
        "result": [
            {
                "name" = "Dilan",
                "place_id" = 1
            },
            {
                "name" = "Milea",
                "place_id" = 1
            }
        ]
    }
},
{
    "identity": {
        "result": [
            {
                "name" = "Ariel",
                "place_id" = 2
            },
            {
                "name" = "Noah",
                "place_id" = 2
            }
        ]
    }
}

nah when i try to echo $response['identity'], the output is shows the first array only, all my operation to $response is only applied for first array only, i can't do any operation to the second array.

what i want is merged all array output into 1 array, LIKE this below:

{
    {
        "identity": {
            "result": [
                {
                    "name" = "Dilan",
                    "place_id" = 1
                },
                {
                    "name" = "Milea",
                    "place_id" = 1
                }
            ]
        }
    },
    {
        "identity": {
            "result": [
                {
                    "name" = "Ariel",
                    "place_id" = 2
                },
                {
                    "name" = "Noah",
                    "place_id" = 2
                }
            ]
        }
    }
}

here my controller

thank you! your help is very needed^^

you don't need to merge . you need to loop over $response and perform task because if merge then it will be same as before (as you mention above merge code) — Kamlesh Paul
– Kamlesh Paul, Commented Sep 28, 2020 at 7:02
btw the output of $response is string, when i try to convert to array like $test = json_decode($response, true); dd($test); then, its only execute the first array which only dump the first array only — mrobbizulfikar
– mrobbizulfikar, Commented Sep 28, 2020 at 7:08
I don't think doing echo $response; will output an array. How do you build the "array" ? — executable
– executable, Commented Sep 28, 2020 at 7:08
@executable when i try dd($response); without doing json_decode, the output is still the first array only — mrobbizulfikar
– mrobbizulfikar, Commented Sep 28, 2020 at 7:10

ahmedkandil · Accepted Answer · 2020-09-28 07:40:03Z

1

why yo need to do this, you can marge all "result" in one array like this

$allResult =[]; 
foreach($arrayes as $array){

      $allResult = array_merge($allResult,$array['identity']['result']);
 }

edited Sep 28, 2020 at 7:40

answered Sep 28, 2020 at 7:30

ahmedkandil

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2 Comments

mrobbizulfikar Over a year ago

but its not dynamic, when the $response is showing 5 array, i think i can't use this code, btw thanks for response!

ahmedkandil Over a year ago

if you need to dynamic it use ``` $allResult =[]; foreach($arrayes as $array){ $allResult = array_merge($allResult,$array['identity']['result']); } ```

AmirAli Esteki · Accepted Answer · 2020-09-28 07:46:33Z

1

the problem is about your json syntax. because you should write

[
    {"identity": {
        ...
    }}
]

instead of:

{
    {"identity": {
        ...
    }}
}

please pay attention to first brackets and accolades. in your json sample "indentifies" must define in an array and at last pass it into a loop that my suggest is foreach iterates. but it's not neccesary to use loop and you can access to every indices of your array with its key. json sample and code:

<?php

// json
$json = '[{
    "identity": {
        "result": [{
            "name": "Dilan",
            "place_id": 1
        }, {
            "name": "Milea",
            "place_id": 1
        }]
    }
}, {
    "identity": {
        "result": [{
            "name": "Ariel",
            "place_id": 2
        }, {
            "name": "Noah",
            "place_id": 2
        }]
    }
}]';

// decode json
$json = json_decode($json, true);

// pass your json to foreach
foreach($json as $json_index){

    // print every indice to process it
    print_r($json_index);
    
    // or getting your result parameters
    foreach($json_index['identity']['result'] as $result){
        echo($result['name'] . ' = ' . $result['place_id']);
        echo PHP_EOL;
    }

}



// or



print_r($json[1]);
?>

edited Sep 28, 2020 at 7:46

answered Sep 28, 2020 at 7:36

AmirAli Esteki

5623 silver badges13 bronze badges

2 Comments

mrobbizulfikar Over a year ago

ok thanks for that response, i can do that, but i cant get the value from an element of that array, its still shows the first array when i try to dd($json); but when print_r or var_dump ($json), its shows all of array data

AmirAli Esteki Over a year ago

@MuhammadRobbiZulfikar i tested my code and it was ok. it show every each loop "name" param. but i don't got your mean. please w8 for others. maybe them can solve your problem

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