How to get array of object's keys and values in powershell script?

Question

I have an array of object in a below format

$test = @(2 :{1,3,5}, 3 : {2,4,6})

I want to extract objects of keys and values from $test array.

Here is my powershell script to perform the above task,

$testnumbers = @(2,3)
$testStores = @{}
$testInfo = $null
foreach ($tn in $testnumbers) {
    $testInfo = @{}
    for($i=0;$i -lt $tn;$i = $i+1) {
    $testPrompt = Read-Host -Prompt "Assign the test numbers"
    $testInfo += $testPrompt
    }
$testInfoSet = {$tn = $testInfo}
$testInfoObj = New-Object psobject –Property $testInfoSet
$testStores += $testInfoObj
}

Please provide a solution, Thanks in advance!

Your $test value is syntactically invalid. You probably meant to use a hashtable, which is created with @{ ... }, not @(...). — mklement0
– mklement0, Commented Sep 28, 2020 at 13:14

dno · Accepted Answer · 2020-09-28 14:08:25Z

6

I think you may want to setup your hashtable like so...

$test = @{2 = (1,3,5); 3 = (2,4,6)}

foreach($item in $test.GetEnumerator()){
    echo $item.key
    echo $item.value
}

edited Sep 28, 2020 at 14:08

answered Sep 28, 2020 at 11:58

dno

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2 Comments

mklement0 Over a year ago

As an aside: While Write-Output, whose built-in alias is echo, is the right tool for outputting data, you typically don't need to use it explicitly, because PowerShell implicitly outputs (to the success data stream) any expression or command that isn't captured or redirected; e.g., just $foo by itself has the same effect as Write-Output $foo / echo $foo. While there is no harm in using Write-Output, consider showcasing PowerShell's implicit output feature instead (possibly with an explanatory comment), so as to promote PowerShell-idiomatic solutions.

mklement0 Over a year ago

Glad to hear we agree, but I suggest you actually update your answer with this information, for the benefit of future readers. Once you have done so, you can flag my first and this comment as "No longer needed" (or ping me, so I can remove them myself).

Brendan Harris · Accepted Answer · 2022-03-28 23:42:34Z

2

I agree with @dno and the comments. I have added to this with the output so you can see it working as explained.

$test = @{2 = (1,3,5);3 = (2,4,6);}

foreach($item in $test.GetEnumerator()){
    $key = $item.key
    $value = $item.value
    Write-Output $key $value
}

answered Mar 28, 2022 at 23:42

Brendan Harris

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