Getting Pygame keyboard input and check if it's a number

Question

I am trying to get keyboard input using Pygame using this command:

if event.type == pg.KEYDOWN:
    # ADD KEYBOARD EVENTS
    keys = pg.key.get_pressed()

I want to check if the button pressed represents a number, I already know how to check if a string represent a number using try/except command, but, in my code keys is not a string, it is a huge tuple - and I don't know how to get it in an efficient way because every time I look in the internet on how to get keyboard input, they need to equate keys to something like pygame.pygame.K_LEFT and I don't want to do this for each number and furthermore every number in the number-pad (right side).

Is there an efficient way to determine if a user clicked on a number? Thanks!

Rabbid76 · Accepted Answer · 2020-09-29 17:07:53Z

4

pygame.key.get_pressed() returns a list with the state of all keyboard buttons. This is not intended to get the key of a keyboard event. The key that was pressed can be obtained from the key attribute of the pygame.event.Event object:

if event.type == pg.KEYDOWN:
    if event.key == pg.K_a:
        # [...]

unicode contains a single character string that is the fully translated character:

if event.type == pg.KEYDOWN:
    if event.unicode == 'a':
        # [...]

4 Comments

0Interest Over a year ago

Hi thanks for the answer! It does work! Is there a way to check if a backspace is pressed using event.unicode ?

Rabbid76 Over a year ago

@StackOMeow a backspace can be recognized by event.key == pg.K_BACKSPACE or pg.key.name(event.key) == "backspace"

0Interest Over a year ago

I am trying if event.type == pg.K_BACKSPACE and len(current_id) > 0: below the if event.type == pg.KEYDOWN: and it still does not work, assume current_id 's length is indeed bigger than 0 (I checked it) is it true how I wrote it? Thanks

Rabbid76 Over a year ago

@StackOMeow event.type -> event.key

score 0 · Accepted Answer · 2022-08-15 17:06:31Z

0

The following code offers quite a neat solution, it ignores all inputs that aren't numbers without even using try/except:

if event.type == pg.KEYDOWN and event.unicode.isdigit():
    print(int(event.unicode))

I wasn't able to find a way to do this that was more compact on the web, so worked out this solution by researching how to check if a string is an integer.

How can I check if a string represents an int, without using try/except?

edited Aug 15, 2022 at 17:06

answered Feb 10, 2022 at 23:48

user7857115

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