React Native AsyncStorage async function return

Question

I have a helper function:

export async function isFavorite(id) {
  try {
    let favorites = await AsyncStorage.getItem("@rn-food-app:favorites");
    if (favorites) {
      return JSON.parse(favorites).includes(id);
    }
    return false;
  } catch (error) {
    return false;
  }
}

which I'm calling like this:

class DetailScreen extends React.Component {
  constructor(props) {
    super(props);
    this.state = {
      recipe: null,
      isFavorite: false,
    };
  }

  componentDidMount() {
    const { route } = this.props;

    if (route.params && route.params.recipeId) {
      const recipe = getRecipe(route.params.recipeId);
      this.setState(
        {
          recipe,
        },
        () => {
          this.checkIfFavorite();
        }
      );
    }
  }

  checkIfFavorite() {
    const { recipe } = this.state;

    console.log(isFavorite(recipe.id));
  }

... ... ...

but the console.log() returns something like this

Promise {
  "_U": 0,
  "_V": 0,
  "_W": null,
  "_X": null,
}

instead of a bool.

I can make it work like this:

export async function isFavorite(id) {
  try {
    return await AsyncStorage.getItem("@rn-food-app:favorites");
  } catch (error) {
    return false;
  }
}

and then in the DetailScreen component

  checkIfFavorite() {
    const { recipe } = this.state;

    isFavorite(recipe.id)
      .then((res) => {
        const favorite = JSON.parse(res).includes(recipe.id);
        console.log(favorite);
      })
      .catch((err) => console.log(err));
  }

This works but why doesn't the approach above work? I wanted to extract all this logic into a helper function so I can simply call isFavorite: bool inside my components without extra logic.

yesIamFaded · Accepted Answer · 2020-10-01 08:08:01Z

1

It seems like you are not resolving your promise correctly thats why you get that weird looking console.log

Take a look at this example and change it to your needs - when getting the item from AsyncStorage I am calling 2x .then() calls and 1x .catch() call.

You can store and retrieve your data like this with AsyncStorage:

  const storeData = async (key, value) => {
    try {
      await AsyncStorage.setItem(key, value); 
    } catch (error) {
      console.log(error);
    }
  };

  const getData = async key => {
    try {
      const data = await AsyncStorage.getItem(key);
      if (data !== null) {
        console.log(data);
        return data;
      }
    } catch (error) {
      console.log(error);
    }
  };

then call getData with the key name like you stored your value wherever you want and set the key to a state value.

Store the value:

storeData("@rn-food-app:favorites", the value);

get the value:

  await getData"@rn-food-app:favorites") 
    .then((data) => data)
    .then((value) => this.setState({ isFavorite: value }))
    .catch((err) => console.log("AsyncStorageErr: " + err));

answered Oct 1, 2020 at 8:08

yesIamFaded

2,0683 gold badges29 silver badges52 bronze badges

Sign up to request clarification or add additional context in comments.

1 Comment

dallion Over a year ago

Yes this approach works, I just thought that the first promise inside getData would handle this and you won't need to call await getData() ... later on

mavarazy · Accepted Answer · 2020-10-01 08:15:36Z

0

You are logging out Promise instead of an actual result of a Promise, something like this would:

 async checkIfFavorite() {
    const { recipe } = this.state;
    const isFav = await isFavorite(recipe.id) 

    console.log(isFav);
  }

or something along those lines would work

answered Oct 1, 2020 at 8:15

mavarazy

7,7351 gold badge38 silver badges61 bronze badges

Collectives™ on Stack Overflow

React Native AsyncStorage async function return

2 Answers 2

1 Comment

Comments

Your Answer

Hot Network Questions

Collectives™ on Stack Overflow

2 Answers 2

1 Comment

Comments

Your Answer

Sign up or log in

Post as a guest

Related