I have this problem I push data this way into array.
this.checkedList.push({"customer_id" : option.id });
How can I splice this value out again? Without key this is working:
this.checkedList.splice(option.id,1);
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3 Answers
You could use the the findIndex prototype method on the array to find key for the element you're looking for, e.g.
let index = this.checkedList.findIndex((element) => element["customer_id"] == option.id);
and then splice the array as you'd normally do.
this.checkedList.splice(index, 1);
Since this would be the last value inserted, you can simply pop this value out
let k = [ {name: 'John'}, {name: 'Doe'} ];
k.push({ name: 'Peter'})
console.log(k)
k.pop()
console.log(k)
2 Comments
SaschaK
Thanks, but it is not last value
Owen Kelvin
Noted, Please update the question with more information about the structure of your component
You are adding an object to the end of your array. Have a look at the following snippet:
// create an array and add an object to it - retrieve via index
const myArr = [];
const newLengthOfArray = myArr.push({"customer_id": 23});
console.log(`Added an element at index ${newLengthOfArray - 1} now containing ${newLengthOfArray} elements`);
const myObject = myArr[newLengthOfArray - 1];
console.log("Your element:", myObject);
// adding more elements
myArr.push({"customer_id": 20});
myArr.push({"customer_id": 21});
myArr.push({"customer_id": 27});
// use find(predicate) to find your first object:
const theSameObject = myArr.find(el => el.customer_id === 23);
// be carefull! find will return the FIRST matching element and will return undefined if none matches!
console.log("Your element found with find:", theSameObject);Be carefull since find() will return undefined if no item matches and will only return the very first item that matches! Order is important!