PHP global variables

Question

Why does the following result in an error message? (it is declared inside a function in PHP by the way; $a and $b are alphabetic values, not numeric)

global $pre[''.$a.''], $predis[''.$b.''];

Parse error: syntax error, unexpected '[', expecting ',' or ';' in ...

@Rocket even if it is alphabetical and not numeric (ex: "abc" and not "123")? — Adam Strudwick
– Adam Strudwick, Commented Jun 21, 2011 at 2:08
Yes that is correct you don't need the '' even with a non-numeric key. — GWW
– GWW, Commented Jun 21, 2011 at 2:13

GWW · Accepted Answer · 2011-06-21 02:03:51Z

6

global $pre, $predis;

Then use $pre and $predis how you want.

answered Jun 21, 2011 at 2:03

GWW

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shmeeps · Accepted Answer · 2011-06-21 02:05:19Z

6

I may be mistaken, but I believe you cannot selectively use keys as globals. You would have to do

global $pre, $predis;

and then use the keys.

The problem lies in that while the variables $pre and $predis have unique identifiers, the keys are only identified in reference to their variables, such that $var1['key'] != $var2['key']. There is no way to assign that specific key to an identifier while making it global, at least in one step. You could however, use an intermediate variable, like

$prekey = $pre['key'];
global $prekey;

answered Jun 21, 2011 at 2:05

shmeeps

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Tomasz Kowalczyk · Accepted Answer · 2014-08-05 19:05:12Z

6

You can't make array index global. In this case, only $pre and $predis may be global and you can use their contents as you need:

global $pre, $predis;

edited Aug 5, 2014 at 19:05

answered Jun 21, 2011 at 2:04

Tomasz Kowalczyk

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