Get Method name with parameters and its values on exception in Java

Question

I have a sample program as follows

public static void enterText(WebElement loc, String value) {
    try {
        loc.clear();
        System.out.println("Text cleared successfully");
    } catch (Exception e) {
        // exception handling
    }
}

On executing loc.clear(), a runtime exception occurs. Is there a way I can get the method name with parameters after exception happens. I need to get this enterText(WebElement loc, String value).

Does this answer your question? Java exception handling

flaxel
– flaxel

2020-10-04 18:38:11 +00:00
Commented Oct 4, 2020 at 18:38 — flaxel
– flaxel, Commented Oct 4, 2020 at 18:38

Mohammed Deifallah · Accepted Answer · 2020-10-04 15:53:50Z

0

You shall print the trace of the exception via this call: e.printStackTrace() inside catch block.

answered Oct 4, 2020 at 15:53

Mohammed Deifallah

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2 Comments

chinnu Nish Over a year ago

No..that would not give me the argument details wit which the method was invoked.

Mohammed Deifallah Over a year ago

@chinnuNish You can print the arguments in the catch block if you need

Abra · Accepted Answer · 2020-10-04 18:35:04Z

0

You just need to add a "print" statement in the catch block.

public static void enterText(WebElement loc, String value) {
    try {
        loc.clear();
        System.out.println("Text cleared successfully");
    }
    catch (Exception e) {
        System.out.printf("ERROR: enterText( %s , %s )%n", loc, value);
        e.printStackTrace();
    }
}

answered Oct 4, 2020 at 18:35

Abra

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