Get substring using regex

Question

I have some strings Like

1.IND_FROM_ONE_TO_FIVE  
2.IND_FROM_FIVE_TO_TEN  
3.BS_FROM_ONE_TO_FIVE 
4.BS_FROM_FIVE_TO_TEN   
5.OP_FROM_ONE_TO_FIVE  
6.OP_FROM_FIVE_TO_TEN

And I want to cut from all of them everything before the first "" include ""!!!.

Something like :

1.IND_FROM_ONE_TO_FIVE => FROM_ONE_TO_FIVE

2.IND_FROM_FIVE_TO_TEN => FROM_FIVE_TO_TEN

3.BS_FROM_ONE_TO_FIVE => FROM_ONE_TO_FIVE

4.BS_FROM_FIVE_TO_TEN => FROM_FIVE_TO_TEN etc.

I have tried /[^_]*/ but it returns IND_FROM_ONE_TO_FIVE => _FROM_ONE_TO_FIVE (did not cut first "_")

How could I make it on java?

The fourth bird · Accepted Answer · 2020-10-06 08:23:21Z

2

You can prepend an anchor and match the underscore after is as well. In the replacement use an empty string.

^[^_]*_

Regex demo | Java demo

Using replaceFirst you can omit the anchor:

System.out.println("IND_FROM_ONE_TO_FIVE".replaceFirst("[^_]*_", ""));

Output

FROM_ONE_TO_FIVE

edited Oct 6, 2020 at 8:23

answered Oct 6, 2020 at 8:13

The fourth bird

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Comments

Thân LƯƠNG Đình · Accepted Answer · 2020-10-06 14:44:41Z

1

You could use a capturing group to extract substring that you want to.

^[^_]+_(.*)

I also tried to test result on Java.

import java.util.regex.*;
public class MyClass {
    public static void main(String args[]) {
        String mydata = "BS_FROM_FIVE_TO_TEN";
        Pattern pattern = Pattern.compile("^[^_]+_(.*)");
        Matcher matcher = pattern.matcher(mydata);
        if (matcher.find())
        {
            System.out.println(matcher.group(1));
        }
    }
}

Result

FROM_FIVE_TO_TEN

answered Oct 6, 2020 at 14:44

Thân LƯƠNG Đình

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Comments

Alexander Mashin · Accepted Answer · 2020-10-06 09:01:05Z

0

You can use matching rather than replacing: take the first and only capture from this regex (multiline): ^\d+\.[^_]+_(.*)$ (https://regex101.com/r/Y3Ztv4/1).

answered Oct 6, 2020 at 9:01

Alexander Mashin

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