I am trying to get the link under a button ('Click Here To Play') on a webpage:
This is the page inspect in Chrome.
I am trying to get the highlighted "href" from <a href="https://vidtodo.com/.... This is my code:
from selenium import webdriver
url = 'https://www1.swatchseries.to/freecale.html?r=qepyJmjdCI6Ilo2SWFPdlk51dDBoMSmtxeHFnWXBbVOEJrcVdVMXhPT2t0bUZEZzNtNEd5ZVhCNHYrWnZkT0NZYzdZaWpmZlB0alEiLCJpdiI6IjFmYTdhMzZjYjJhODc1ZmIxODQ4MzVhZDc2N2MyYjNiIiwicyI6Ijc2NTZiMDg0MDFhNmQ1NjYifQ=='
driver = webdriver.Chrome('drivers/chromedriver.exe')
driver.maximize_window()
driver.get(url)
elements = driver.find_elements_by_xpath('/html/body/div[2]/div[2]/div/div[2]/div/div/div/div/div/div/div/div[2]/a')
for element in elements:
print(element.get_attribute('href'))
However, I am getting this as result, rather than the link I want:
http://www1.swatchseries.to/
Process finished with exit code 0
Any suggestions on how to get the link I need?

