How to sort a javaScript array according to his duplication count

Question

I have an array with some duplicates value. I have removed all duplicates value and get his count(repeat). Now I have to sort this data according to his count.

Example:

let duplicatis_data = ['a','a','b','b','b','c','c','c','c','d','e'];

Expected output

    c->4
    b->3
    a->2
    d->1
    e->1

There is lots of example with removing the duplicates and return the count but they did not make filter according to count. So this is not a duplicate of those questions like below.

How to count duplicate value in an array in javascript

Does this answer your question? Javascript: sort elements in array by their frequencies — Rahul Bhobe
– Rahul Bhobe, Commented Oct 10, 2020 at 19:24
Group them, turn the object into an array (Object.entries()) and sort that entry -> done — Andreas
– Andreas, Commented Oct 10, 2020 at 19:27
@RahulBhobe I want the count for that frequency as well as I mention the expected output. — Mannu saraswat
– Mannu saraswat, Commented Oct 11, 2020 at 7:35

Rahul Bhobe · Accepted Answer · 2020-10-11 07:53:15Z

1

Calculate the frequency and then sort the array based on the frequency:

let duplicatis_data = ['a','a','b','b','b','c','c','c','c','d','e'];

   
const freq = duplicatis_data.reduce((c, v) => (c[v] = (c[v] || 0) + 1, c), {});

const result = Object.entries(freq).sort((x, y) => y[1] - x[1]);

console.log(JSON.stringify(result));

edited Oct 11, 2020 at 7:53

answered Oct 11, 2020 at 7:46

Rahul Bhobe

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3 Comments

Mannu saraswat Over a year ago

I already get that result but my question is how can I sort that data? like{ "c": 4, "b": 3, "a": 2, "d": 1, "e": 1 }

Rahul Bhobe Over a year ago

The new result is an array, and not an object. There is no notion of an "order" in an object.

Mannu saraswat Over a year ago

That's fine. Thanks, you save my day.

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