How can i break a for in loop from nested forEach Function in Javascript?

Question

I have a this loops

for (var key in params) {
  if (Array.isArray(params[key])) {
    params[key].every(function(item) {
      let value = something(item.start, item.end);
      if (value === item.start || value == item.end) {
        return false // break
      }
    })
  }
}

When i set return false to stop the every() function i also want to stop the first loop. How can i do that? I tried this:

OUTER_LOOP: for (var key in params) {
  if (Array.isArray(params[key])) {
    params[key].every(function(item) {
      let value = something(item.start, item.end);
      if (value === item.start || value == item.end) {
        return false // break
        break OUTER_LOOP; // not working
      }
    })
  }
}

but it doesn't work in this way... so how can i stop the every() function and the first loop at same time correctly?

can you share the content of param

brk
– brk

2020-10-20 13:08:35 +00:00
Commented Oct 20, 2020 at 13:08 — brk
– brk, Commented Oct 20, 2020 at 13:08

Nina Scholz · Accepted Answer · 2020-10-20 13:23:40Z

1

You could take Array#some and return true for exit some and use the returned value of some for breaking the loop.

for (var key in params) {
    if (Array.isArray(params[key])) {
        const
            leave = params[key].some(item => {
                let value = something(item.start, item.end);

                // exit condition should return true/truthy value
                // for leaving the outer loop
                return value === item.start || value == item.end;
            });

        if (leave) break;
    }
}

edited Oct 20, 2020 at 13:23

answered Oct 20, 2020 at 13:04

Nina Scholz

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8 Comments

Niklas Over a year ago

thanks, but return true doesn't stop the for (var key in params) loop

Nina Scholz Over a year ago

yes, please see edit. the result needs to bubbled outside with a check.

Niklas Over a year ago

thank you, I have updated my code again, because I forgot something... does it still work with some()? could you take a look again?

Niklas Over a year ago

thanks for you update. But i have one problem. something() returns for e.g. a float value like 0.99 if the item.end is 1 so the loops ends before 1 so in my console.log() i see it ends with 0.99 instead of 1. How can i change the if condition, so i can also see 1 once and then the loop breaks? or do i need to pass my other stuff before return value ?

Nina Scholz Over a year ago

you could round the value ...?

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