convert linspace array to 1d array on python

Question

I'm using linspace to generate an array of 100 elements, the result's shape is (100,) but I want to obtain an array with the following shape (100, 1). How can I do it? I tried reshape but it does not give the required result. Here is an exmaple :

import numpy as np
om1 = np.linspace(-50, 50, 100);
om = np.random.randn(100,1);
print(shape(om1))
print(shape(om))

Output :

>>> (100, )
(100, 1)

Your code isn't valid python, there is no shape function. Did you mean om1.shape? — Michael Szczesny
– Michael Szczesny, Commented Oct 21, 2020 at 10:22

xtofl · Accepted Answer · 2020-10-21 10:12:49Z

1

Doesn't the numpy array have a reshape method? https://numpy.org/doc/stable/reference/generated/numpy.ndarray.reshape.html#numpy.ndarray.reshape

om1 = np.linspace(-50, 50, 100).reshape( (100, 1) )

answered Oct 21, 2020 at 10:12

xtofl

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3 Comments

ynasroal Over a year ago

That works for me ! Thanks @xtofl ! I was using reshape in the wrong way ig...

xtofl Over a year ago

You could say that. Since I have made the same mistake, I dare to say that np.array.reshape has been given the wrong name. Had it been np.array.reshaped, many frustrating developer-hours would have been saved.

ynasroal Over a year ago

No, I just typed om=reshape(len(om),1) instead of om=om.reshape(len(om),1) I didn't pay attention sorry!

Michael Szczesny · Accepted Answer · 2020-10-21 10:28:21Z

0

You can use reshape to add the missing dimension without knowing the length of your array

om1.reshape(-1,1)

With -1 as one dimension the length of that dimension is inferred.

answered Oct 21, 2020 at 10:28

Michael Szczesny

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1 Comment

ynasroal Over a year ago

Thanks @MichaelSzczesny ! That's a useful information!

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