Repeat binary number to be the same length as another number in python

Question

Say I have a binary number message of 0100110101100101 and a binary key of 001.

How can I repeat the key to be the same length as the message? As in take the length of the message and then repeat the pattern of the key till the length of the message is reached?

In the example the output should be 0010010010010010

Thanks.

Mayank Porwal · Accepted Answer · 2020-10-22 06:49:27Z

1

You can use python's list slicing:

In [1599]: a = '0100110101100101'
In [1602]: key = '001'

In [1608]: factor = len(a) // len(key)
In [1606]: remainder = len(a) % len(key)

In [1625]: if factor == 0:
      ...:     print("pattern greater than the string")
      ...: else:
      ...:     answer = (key * factor) + key[:remainder]
      ...: 

In [1614]: answer
Out[1614]: '0010010010010010'

edited Oct 22, 2020 at 6:49

answered Oct 22, 2020 at 6:02

Mayank Porwal

34.2k9 gold badges45 silver badges65 bronze badges

Sign up to request clarification or add additional context in comments.

2 Comments

Ananth Over a year ago

Mayank, this solution prints the string even when the pattern is smaller than the string. Maybe it will be good to add a condition if needed by @Sulhan!

Mayank Porwal Over a year ago

@Ananth Updated my solution to handle key is greater than message case. Thanks.

Collectives™ on Stack Overflow

Repeat binary number to be the same length as another number in python

1 Answer 1

2 Comments

Your Answer

Hot Network Questions

Collectives™ on Stack Overflow

1 Answer 1

2 Comments

Your Answer

Sign up or log in

Post as a guest

Related