How to avoid python running file in the directory where the code is located?

Question

I'm writing a script that will download an executable from the internet, which will create more files. Now, if I download the file, it will be downloaded to the directory I told it, but when I open it using os.startfile(), it creates the files to the directory where the python script is located. How can I avoid that?

Move the file before opening it? So that the created files are in that directory — Collin Heist
– Collin Heist, Commented Oct 23, 2020 at 19:59

void main · Accepted Answer · 2020-10-23 20:06:40Z

1

Either you can move the .py file to any other directory. or You can use os.chdir() to change the current working directory of the script during the runtime.

os.chdir('/path/to/directory')

answered Oct 23, 2020 at 20:06

void main

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rdas · Accepted Answer · 2020-10-23 20:01:17Z

1

Do a os.chdir() before trying to run the executable:

os.chdir('<the target folder where you want the files to be created>')
...
os.startfile('<path to where the executable was downloaded>')

answered Oct 23, 2020 at 20:01

rdas

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