I am reading a Python script which has this syntax a, b = foo(c, d)(f, g). It is the first time I am seeing this syntax. How do I have to interpret that?
Unfortunately I am not authorized to share the code.
foo has a structure like the following.
def foo(n):
def todo(func):
def dodo(*args, **kargs):
...
...
...
return func(*args, **kargs)
return dodo
return todo
Hia all, a,b = foo(c,d)(f,g) means
foo(c,d))foo(c,d)(f,g) (func(f,g)))a,b = foo(c,d)(f,g) (a = foo(c,d)(f,g)[0]))b = foo(c,d)(f,g)[1])so a,b = foo(c,d)(f,g) is a way to write
save = foo(c,d)(f,g)
a = save[0]
b = save[1]
Examples:
(warning: c,d,f and g as are ints in my Examples)
foo returns a function. Example:
def foo(c,d):
if c+d > 10:
return func1
else:
return func2
so you execute func1 (or func2) with f and g,
then you save output 1 to a and output2 to b
Example for func1 and func2:
def func1(f,g):
return [f+1,g+1]
def func2(f,g):
return [f-1,g-1]
then would the snippet would be used as following:
c = 5
d = 8
f = 19
g = 4
def func1(f,g):
return [f+1,g+1]
def func2(f,g):
return [f-1,g-1]
def foo(c,d):
if c+d > 10:
return func1
else:
return func2
a,b = foo(c,d)(f,g)
if we add prints to the end then
a will be 20
and b will be 5.
foo(c, d)is probably returning another function that accepts two parameters.a,b- but without the implementation of foo this is not really answerable nor is it in and of itself a good question for SO.foo(itself a function or other type of callable). The latter is returning a sequence of some of length 2 whose element are being "unpacked" and assigned to the variablesa&b.