Python selenium send click to input button

Question

I'm trying to use python and selenium webdriver to click in a submit button of a specific form, below is the source code of the element that I want to click:

<input type="submit" name="post" tabindex="5" value="Submit" class="btn btn-primary btn-xs btnmain" accesskey="s">

And here is the python expression that I'm using to click on it:

text_area = wd.find_element_by_id('qreply')
text_area.send_keys("TEST STRING")
wd.find_element_by_xpath("//button[contains(@class,'btn btn-primary btn-xs btnmain')]").click()

The problem is, that for some reason, my script appears to not click at the button and the information is not sent.

Any suggestion how I can solve it?

DMart · Accepted Answer · 2020-10-26 16:32:17Z

1

wd.find_element_by_xpath("//button[contains(@class,'btn btn-primary btn-xs btnmain')]").click()

Is that xpath right? Your html says it's a input tag, not button.

Try

wd.find_element_by_xpath("//input[contains(@class,'btn btn-primary btn-xs btnmain')]").click()

Also consider a better xpath like:

wd.find_element_by_xpath("//input[@name='post']").click()

answered Oct 26, 2020 at 16:32

DMart

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Comments

kennysliding · Accepted Answer · 2020-10-26 15:13:38Z

0

for the send keys part

text_area = wd.find_element_by_id('qreply')
text_area.click() # you need to click it before typing, just like how you would do it manually
text_area.send_keys("TEST STRING")

for the submit button, my guess is your xpath is too generic that it extracted another button that has the same classes. Try to print the extracted button and see if it is the one you want first as your code for clicking seems fine.

answered Oct 26, 2020 at 15:13

kennysliding

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1 Comment

Paul Mark Over a year ago

Thanks for the text area tip, and about the button, he is the only that uses this class, I've tried to click by name, bu got the same error.

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